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2 years ago

18x26=? I don't get how to do this

Mathematics

1 answer:

elena-s [515]2 years ago

6 0

Answer:

468

Step-by-step explanation:

Set it up like the following-

--------

108

360

--------

408

Take the right number (6) and multiply it with 18

6 x 18 = 108

Now do the same with 2, except put a 0 at the end

2 x 18 = 36

add 0

360

Add both numbers-

360 + 108 = 468

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2 years ago

Which represent geometric sequences? Check all that apply.

Anon25 [30]

The sequence that represents a geometric sequence can be seen in the 1st option and the 4th option in the image attached.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a set of integers that follows a pattern in which the following term is determined by multiplying the previous one by a factor known as the common ratio (r).

$\mathbf{a_n = a_{n-1}\times r}$ or $\mathbf{a_n = a_{1}\times r^{n-1}}$

$\mathbf{a_2 = a_{2-1}\times r}$

$\mathbf{a_2 = a_{1}\times r}$

$\mathbf{ r= \dfrac{a_2}{a_1}}$

From the options given, the options that have geometric sequences are:

3/16, 3/8, 3/4, 3/2

r = (3/8)/(3/16) = (3/4)/(3/8) = 2 (proves that it is a geometric sequence)

3, 9, 27, 81
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4 0

1 year ago

I need help asap please and thank you

salantis [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

7 0

3 years ago