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mihalych1998 [28]
3 years ago
8

Pyramid is 972 cubic in. What are dimensions

Mathematics
1 answer:
stepan [7]3 years ago
5 0
A measurable extent of some kind, such as length, breadth, depth, or height
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I'm pretty sure it would be y=2x+9
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Need help asap please
Lesechka [4]

Answer:

C ) y= -7x -7 is the answer. Thankyou

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I need help with this question.
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The region describes a rectangle. F(x,y) is optimized at the intersecting points around the rectangle.
You can try plugging in (-3,-5) , (-3,4), (4,4) , (4,-5) and see which one gives you the largest value.

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4 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
Naddika [18.5K]

Answer:

The rocket will hit the ground after about 8.20 seconds.

Step-by-step explanation:

The height of the rocket <em>y</em>, in feet, <em>x</em> seconds after launch is modeled by the equation:

y=-16x^2+121x+83

We want to find the time at which the rocket will hit the ground.

If it hits the ground, the height of the rocket <em>y</em> will be 0. Thus:

0=-16x^2+121x+83

We can solve for <em>x</em>. Factoring (if possible at all) or completing the square can be tedious, so we can use the quadratic formula:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = -16, <em>b</em> = 121, and <em>c </em>= 83. Substitute:

\displaystyle x=\frac{-(121)\pm\sqrt{(121)^2-4(-16)(83)}}{2(-16)}

Simplify:

\displaystyle x=\frac{-121\pm\sqrt{19953}}{-32}

Divide everything by -1 and simplify the square root. The plus/minus will remain unchanged:

\displaystyle x=\frac{121\pm3\sqrt{2217}}{32}

Therefore, our two solutions are:

\displaystyle x=\frac{121+3\sqrt{2217}}{32}\approx 8.20\text{ or } x=\frac{121-3\sqrt{2217}}{32}\approx -0.63

Since time cannot be negative, we can ignore the second solution.

Therefore, the rocket will hit the ground after about 8.20 seconds.

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3 years ago
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