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AlexFokin [52]
3 years ago
11

A balloon inflated with three breaths of air has a volume of 1.7 L. At the same temperature and pressure, what is the volume of

the balloon if five more same-sized breaths are added to the balloon? A balloon inflated with three breaths of air has a volume of 1.7 L. At the same temperature and pressure, what
is the volume of the balloon if five more same-sized breaths are added to the balloon?
Chemistry
1 answer:
Karolina [17]3 years ago
7 0

Ans: The final volume of the balloon is 4.5 L

<u>Given:</u>

Volume of balloon inflated with 3 breaths = 1.7 L

<u>To determine:</u>

Volume of balloon after a total of 3+5 = 8 breaths

<u>Explanation:</u>

Volume of the balloon per breath = 1.7 L * 1 breath/3 breaths = 0.567 L

Final volume of balloon after 8 breaths = 0.567 L * 8 breath/1 breath

= 4.536 L

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frutty [35]

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

C = k \times P = \frac{1.65 \times 10^{-3} M }{atm}  \times 4.60 atm = 7.59 \times 10^{-3} M

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

\frac{7.59 \times 10^{-3} mol}{L} \times  1.1 L \times \frac{44.01 g}{mol}  = 0.367 g

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.

C = k \times P = \frac{1.65 \times 10^{-3} M }{atm}  \times 1.28 atm = 2.11 \times 10^{-3} M

\frac{2.11 \times 10^{-3} mol}{L} \times  1.1 L \times \frac{44.01 g}{mol}  = 0.102 g

The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

m = 0.367 g - 0.102 g = 0.265 g

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

Learn more: brainly.com/question/18987224

<em>The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.</em>

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