Answer:
d≈ 1.15 g/cm^3
Explanation:
The density of an object can be found by dividing the mass over the volume.
d= m/v
The mass of the object is 54.3 grams and the volume is 47.18 cubic centimeters.
m= 54.3 g
v= 47.18 cm^3
Substitute the values into the formula.
d= 54.3 g/ 47.18 cm
Divide.
d= 1.150911403136922 g/cm^3
Let’s round to the nearest hundredth. The 0 in the thousandth place tells us to leave the 5 in the hundredth place.
d ≈ 1.15 g/cm^3
The density is about 1.15 grams per cubic centimeter.
Answer:
b. 7.5 x 10^-3
Explanation:
To solve this problem we need to keep in mind the <em>definition of molarity</em>:
- Molarity = moles of solute / liters of solution
With the above information in mind it is possible to calculate the moles of solute, given the volume (10 mL) and concentration (0.75 M) of the solution:
- First we<u> convert 10 mL to L</u> ⇒ 10 mL / 1000 = 0.01 L
Then we <u>calculate the moles of AgNO₃</u>:
- moles of solute = Molarity * Liters of solution
- 0.01 L * 0.75 M = 7.5x10⁻³ mol AgNO₃
<em>One mole of AgNO₃ contains one mole of Ag⁺</em>, thus the number of Ag⁺ moles is also 7.5x10⁻³.
Milk is an example of solid emulsion. Hence, option D is correct.
<h3>What is emulsion?</h3>
An emulsion is defined as a colloid consisting of two or more non-homogenous type of liquids in which one of the liquid contains the dispersion of the different form of liquids.
Emulsion consist of a dispersion of two liquids that are immiscible with each other.
One of the liquids act as the dispersion medium and the other will act as the dispersed phase.
Emulsions are colloids in which both the dispersed phase and dispersion medium are liquids.
Types of Emulsion:
- Oil in water (O/W)
- In this type of emulsion, the oil will be the dispersed phase and water will be the dispersion medium.
- Example of o/w emulsion is milk.
2. Water in oil (W/O)
- In this type, water will be the dispersed phase and oil will be the dispersion medium.
- Margarine is an example of water in oil emulsion.
Milk is an example of solid emulsion. Hence, option D is correct.
Learn more about emulsion, Here:
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Answer:
21.2 grams CH2Cl2
Explanation:
Number of moles: .25
Molar mass of CH2Cl2: 84.93 g/mol
Mass in grams: 84.93(0.250) = 21.2325
Dependent variable: Weight
Independent variable: Amount of food
Explanation:
In experiments such as the one described, there are two or more factors involved, which act as variables. Additionally, these factors can be classified as dependent or independent. The difference between these two is that the independent factor is changed on purpose by the researcher. This occurs with the amount of food as each dog receives a different amount of food and this is controlled by the researcher.
On the other hand, the dependent variable is the main factor analyzed in the experiment or the factor that is modified by the independent variable. In the experiment presented, the dependent variable is weight because in this experiment the focus is to analyze how weight changes with different amounts of food, and this factor is affected by the independent variable.
