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ICE Princess25 [194]
3 years ago
11

You told your sister about creating bullet points with Word 2013. She calls you and says that she created a list of six bullet p

oints, but she can't stop creating more bullets because every time she hits the Enter key another bullet is created. She needs your help. Question 3 options: a) Tell her to hold the Shift key as she hits Enter. b) Tell her to hold the Ctrl key as she hits Enter. c) Tell her to hold the Alt button as she hits Enter. d) Tell her to right-click the mouse as she hits Enter.
Computers and Technology
1 answer:
lapo4ka [179]3 years ago
8 0

Answer:

Tell her to hold the Shift key as she hits Enter.

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Your task is to write a C program that measures the latencies of various system calls. In particular, you want to know 1) the co
tensa zangetsu [6.8K]

Answer and Explanation:

#include <stdio.h>

#include<fcntl.h>

#include <sys/time.h>

#include<time.h>

#define MAX 1000

int main()

{

int pid;

int i,fd ;

char c[12];

FILE *fp;

struct timeval start,end;

double time1,time2,time3;

//open file for writing

fp=fopen("output.txt","w");

 

if(!fp)

{

printf("Not able to open the file output.txt\n");

return -1;

}

for(i = 0; i < MAX ; i++)

{

gettimeofday(&start,NULL);

//invoke getpid call

system(pid = getpid());

//printf("%d\n",start.tv_usec);

}

gettimeofday(&end,NULL);

//printf("%d\n",(end.tv_usec - start.tv_usec));

time1 = ((end.tv_sec - start.tv_sec) + (end.tv_usec - start.tv_usec) / 1000000.0)/MAX;

 

//wtite the time taken to execute getpid to

//to get micro second , divide multiply time by 1000000 , to get nano multiply time by 1000000000

printf("getpid(): %.10f %.10f\n",time1*1000000,time1*1000000000);

fprintf(fp,"getpid():%.10f %.10f\n",time1*1000000,time1*1000000000);

//in similar way execute other two commands ,open and read

 

for(i = 0; i < MAX ; i++)

{

gettimeofday(&start,NULL);

//invoke getpid call

system(open("/dev/null", O_RDONLY ));

//printf("%d\n",start.tv_usec);

}

gettimeofday(&end,NULL);

//printf("%d\n",(end.tv_usec - start.tv_usec));

time2 = ((end.tv_sec - start.tv_sec) + (end.tv_usec - start.tv_usec) / 1000000.0)/MAX;

 

//wtite the time taken to execute getpid to

printf("open(): %.10f %.10f\n",time2*1000000,time2*1000000000);

fprintf(fp,"open():%.10f %.10f\n",time2*1000000,time2*1000000000);

//in similar way execute other two commands ,open and read

fd = open("/dev/dev",O_RDONLY );

//printf("fd = %d\n",fd);

for(i = 0; i < MAX ; i++)

{

gettimeofday(&start,NULL);

//invoke getpid call

system( read(fd,c,10));

//printf("%d\n",start.tv_usec);

}

gettimeofday(&end,NULL);

//printf("%d\n",(end.tv_usec - start.tv_usec));

time3 = ((end.tv_sec - start.tv_sec) + (end.tv_usec - start.tv_usec) / 1000000.0)/MAX;

 

//wtite the time taken to execute getpid to

printf("read(): %.10f %.10f\n",time3*1000000,time3*1000000000);

fprintf(fp,"read(): %.10f %.10f\n",time3*1000000,time3*1000000000);

}

----------------------------------------------------------

//output

//I have written output to standard output also , you can remove that

getpid(): 0.1690000000 169.0000000000    

open(): 0.1890000000 189.0000000000    

read(): 3.1300000000 3130.0000000000

------------------------------------------------------

//Makefile content

prob2.o : prob2.c    

         gcc -c  prob2.c                                                                                                                                      

prob2 : prob2.o                                                                                                                                                

       gcc -o prob2 prob2.o                                                                                                                                    

all   :                                                                                                                                                        

       gcc -o prob2 prob2.c                                                                                                                                    

clean:                                                                                                                                                          

       rm -rf prob2.o  

---------------------------------------

use

$make all

then execute as below

$./prob2

3 0
3 years ago
Write a c++ program to calculate the approximate value of pi using this series. The program takes an input n that determines the
Tanya [424]

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

int main() {

  char choice;

  cout << setprecision(12) << endl;

  while(true) {

      int sign = 1;

      double pi = 0;

      cout << "Enter number of terms: ";

      long n;

      cin >> n;

      for(long i = 1; i < n; i += 2) {

          pi += sign/(double)i;

          sign = -sign;

      }

      pi *= 4;

      cout << "value of pi for n = " << n << " is " << pi << endl;

      cout << "Do you want to try again(y or n)? ";

      cin >> choice;

      if(choice == 'n' || choice == 'N') {

          break;

      }

  }

  return 0;

}

Explanation:

6 0
3 years ago
(10 LC)
barxatty [35]

Answer:

college A

Explanation:

7 0
2 years ago
Digital cameras are less susceptible to UV light.Select one of the options below as your answer:A. TrueB. False
horrorfan [7]
<span>Digital cameras are less susceptible to UV light. TRUE. In fact, there is an existing photography called Ultraviolet Photography. It is a process of photography that records images by using the light from the ultraviolet spectrum. There are two possible ways to use UV in taking photographs: via reflected UV and UV induced fluorescence.</span>
4 0
3 years ago
Read 2 more answers
Write code that declares a variable named minutes, which holds minutes worked on a job,
Mamont248 [21]

The code that carried out the functions indicated above is stated below. It is not be noted that the code is written in C#

<h3>What is C#</h3>

C# is a type-safe, object-oriented programming language. It is pronounced "see sharp"

<h3>What is the code for the above task?</h3>

Using System;            

public class HoursAndMinutes

{

   public static void Main()

   {

      // declaring minutes variable and assigning 197 as given in question

       int minutes = 197;

     // outputing the total minutes , hours

       Console.WriteLine("{0} minutes is {1} hours and {2} minutes.", minutes, minutes/60, minutes%60);

   }

}

// OUT

Learn more about C#:
brainly.com/question/20211782
#SPJ1

8 0
2 years ago
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