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Finger [1]
3 years ago
7

John wrote the numbers 678,901 and 67,890. How many times greater is the value of 7 in 678,901?​

Mathematics
2 answers:
worty [1.4K]3 years ago
4 0

Answer:

The value of 7 in 678,901 is 10 times greater than the value of 7 in 67,890

Step-by-step explanation:

step 1

we have

678,901

Write in expanded form

678,901=600,000+70,000+8,000+900+1

The value of 7 is 70,000

step 2

we have

67,890

Write in expanded form

67,890=60,000+7,000+800+90

The value of 7 is 7,000

step 3

Divide 70,000 by 7,000

\frac{70,000}{7,000}=10

therefore

The value of 7 in 678,901 is 10 times greater than the value of 7 in 67,890

Talja [164]3 years ago
4 0

Answer:

Value of 7 in 678,901 in 10 times greater than the value of 7 in 67,890.

Step-by-step explanation:

Given  : John wrote the numbers 678,901 and 67,890.

To find :  How many times greater is the value of 7 in 678,901?.

Solution : We have given  numbers 678,901 and 67,890.

In 678,901

We can see the 7 is at ten thousand place = 70,000.

In 67,890.

We can see the 7 is at  thousand place = 7,000.

So, we can see 70,000 = 10 * 7000

So, Value of 7 in 678,901 in 10 times greater than the value of 7 in 67,890.

Therefore, Value of 7 in 678,901 in 10 times greater than the value of 7 in 67,890.

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3 0
3 years ago
Question 8. PV = nRT, solve for T please?<br><br>Question 10. C= Wtc÷1000, solve for W, please?​
sp2606 [1]

Answers:

\huge \boxed{T= \frac{P V}{n R} } \\ \\ \\ \\ \huge \boxed{W= \displaystyle \frac{1000C }{tc}}

\rule[225]{225}{2}

Step-by-step explanation:

<h2>8.</h2>

P \cdot V = n \cdot R \cdot T

Dividing both sides by n · R:

\displaystyle \frac{P \cdot V}{n \cdot R} =T

<h2>9.</h2><h2 />

\displaystyle C=\frac{Wtc }{1000}

Multiplying both sides by 1000:

1000C=Wtc

Dividing both sides by tc:

\displaystyle \frac{1000C }{tc}=W

<h2 />

\rule[225]{225}{2}

4 0
3 years ago
(x+y,y+3)=(6,2y) find the value of x and y​
trasher [3.6K]

Step-by-step explanation:

Solution:

Given:-

(X+y,y+3)=(6,2y)

Equating corresponding elements,we get,

X+y=6------(1)

y+3=2y-----(2)

solving equation (2),

y-2y=-3

-y=-3

y=3.

Now, substituting y=3 in equation (1)

X+3=6

X=6-3

X=3

Therefore,. (X,Y) = (3,3)

8 0
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julsineya [31]

Answer:

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Step-by-step explanation:

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7 0
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