<img src="https://tex.z-dn.net/?f=%28-2a%5E%7B4%7Db%5E%7B2%7D%29%5E3" id="TexFormula1" title="(-2a^{4}b^{2})^3" alt="(-2a^{4}b^{

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KatRina [158]

3 years ago

2})^3" align="absmiddle" class="latex-formula">

PLEASE EXPLAIN HOW YOU GOT YOUR ANSWER

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

4 0

Answer:

-8a^12b^6

Step-by-step explanation:

multiply each term with the power

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Use the quadratic formula to solve the equation -3x2-x-3=0

Novosadov [1.4K]

Answer:

$x=\frac{1+\sqrt{35}i}{-6}\,\, and\,\, x=\frac{1-\sqrt{35}i}{-6}\\$

Step-by-step explanation:

the quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= -2, b = -1 and c =-3

Putting values in the formula

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(-3)(-3)}}{2(-3)}\\x=\frac{1\pm\sqrt{-35}}{-6}\\x=\frac{1+\sqrt{-35}}{-6}\,\, and\,\, x=\frac{1-\sqrt{-35}}{-6}\\We\,\, know \,\,that \,\,\sqrt{-1} = i \\x=\frac{1+\sqrt{35}i}{-6}\,\, and\,\, x=\frac{1-\sqrt{35}i}{-6}\\$