Some primitive triples are ... (3, 4, 5) (5, 12, 13) (7, 24, 25) (9, 40, 41) One interesting characteristic of these is that the sum of the last two numbers is the square of the first number.
Any multiple of these will be a Pythagorean triple.
Now consider your list. a) (10, 24, 26) = 2×(5, 12, 13) . . . IS a Pythagorean Triple b) 2×(7, 24, 25) = (14, 48, 50), so (14, 48, 49) is NOT a Pythagorean Triple c) 3×(3, 4, 5) = (9, 12, 15), so (9, 12, 16) is NOT a Pythagorean Triple d) (9, 40, 41) . . . IS a Pythagorean Triple e) 5×(3, 4, 5) = (15, 20, 25) . . . IS a Pythagorean Triple
The sets of side lengths that are Pythagorean Triples are ... (10, 24, 26) (9, 40, 41) (15, 20, 25)
I believe the answer is C. If you were to plug in 1 for t, you would get h=22. Thus, the max height is 22 feet, and the time it took to get there was 1 second.
<em>SInce this continued fraction does not terminate, we can tell that √5 cannot be represented as a terminating fraction - i.e. a rational number. So √5 is an irrational number a little smaller than 214=94 . For better rational approximations you can terminate the continued fraction after more terms.</em>