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lora16 [44]
3 years ago
14

Answer correctly for brainliest and also get a thanks ! Don't answer if you don't know it please !

Mathematics
2 answers:
RSB [31]3 years ago
6 0
I am pretty sure it is 3.
Serggg [28]3 years ago
5 0
Three possible midsegments
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Solve the system of equations and choose the correct ordered pair.
KiRa [710]
<span>4x + 3y = 16
7x + 6y = 31

Note what happens if we mult. the first eqn. by -2:  

-8x - 6y = -32

Combining this with the 2nd equation eliminates the variable y:

</span>-8x - 6y = -32<span>
7x + 6y = 31
--------------------
-x          = -1, or x = 1.  Sub 1 for x in either of the 2 given eqns to find y:

For example:  4(1) + 3y = 16, so 36 = 12, and y = 3.  Sol'n is (1,3).</span>
8 0
3 years ago
Read 2 more answers
Pls help im markin brainliest
mario62 [17]

The answer is 552 in. ^2

Hope this helps!


6 0
3 years ago
Read 2 more answers
(09.02)
Ivenika [448]

Answer:

4th option

Step-by-step explanation:

x² - 2x - 3 = 0 ( add 3 to both sides )

x² - 2x = 3

using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 1)x + 1 = 3 + 1

(x - 1)² = 4

4 0
2 years ago
Find the dimensions of the rectangle with maximum area that can be inscribed in a circle of radius 10.
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

That will be a square with a diagonal of 20

side length of 20sin45

and area of (20sin45)² = 200 units²

prove it you say?

Area of a rectangle is base times height

A = bh

With a radius of 10, the diagonals of any rectangle inscribed will be 20 units

20² = b² + h²

h = \sqrt{400 - b^2}

A = bh

A = b\sqrt{400 - b^2}

Area will be maximized when the derivative is set to zero

           dA/db = \sqrt{400 - b^2} - b²/ \sqrt{400 - b^2}

                   0 = \sqrt{400 - b^2} - b²/ \sqrt{400 - b^2}

b²/\sqrt{400 - b^2} =  \sqrt{400 - b^2}

                  b² = 400 - b²

                2b² = 400

                  b² = 200

                  b = \sqrt{200}

h = \sqrt{400 - b^2}

h = \sqrt{400 - \sqrt{200}^2 }

h = \sqrt{200}

A = bh

A =  \sqrt{200}•\sqrt{200}

A = 200 units²

5 0
3 years ago
Let’s consider all possible rectangles with the same area of 30 square inches.
Mrac [35]

Answer:4 possible rectangles.

Step-by-step explanation:

With all whole numbered dimensions and area of 30sq m is possible when :

Length.width=5*6, 10*3, 15*2,30*1

8 0
3 years ago
Read 2 more answers
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