How many ATP are generated in the electron transport chain? o 2 ООО 32 36

Como se representa la molecula de agua y en cuantas partes

Hitman42 [59]

¡La opinión de un químico sobre el mundo no es tan estrecha como se podría pensar! Sí, empezamos con el átomo, y luego pasamos a las reglas que gobiernan los tipos de unidades estructurales que se pueden hacer con ellos. Se nos enseña tempranamente a predecir las propiedades de la materia en masa de estos arreglos geométricos. Y luego llegamos a H2O, y estamos sorprendidos al descubrir que muchas de estas predicciones están muy lejos, y que el agua (y por implicación, la vida misma) ni siquiera debería existir en nuestro planeta. Pero pronto aprendemos que esta pequeña combinación de tres núcleos y ocho electrones posee propiedades especiales que lo hacen único entre los más de 15 millones de especies químicas que conocemos actualmente. Cuando nos detenemos a reflexionar sobre las consecuencias de esto, la química pasa de ser una ciencia arcana a un viaje de maravilla y placer mientras aprendemos a relacionar el mundo microscópico del átomo con el mundo mayor en el que todos vivimos.

7 0

3 years ago

Read 2 more answers

What are ways that ordinary people can help to keep antibiotic resistance from getting worse?

Studentka2010 [4]

by WASHING THEIR HANDS EVERY TIME THEY HANDLE FOOD OR USE THE LOUI!!!!!

8 0

3 years ago

4. Some animals that live in the desert don't move often, if at all, during the day in

FinnZ [79.3K]

Answer: Estivation

Explanation:

Non-mammalian animals that cannot maintain their body temperature by its own. They need to adapt certain phenomenon to survive in the existing conditions.

The animals in the desert like snakes, reptiles, North American tortoise, also maintain their body temperature and maintain an adequate amount of water inside the body.

The animals in the desert do not move out during the daytime in order to conserve water and energy.

This phenomenon is season and is known as estivation.

3 0

3 years ago

In Experiment 5, how did the shape of the epidermal cells in the outer skin surface slide compare to the shape of the epidermal

Phoenix [80]

Answer:

The correct answer is B. The cells in the outer skin surface appeared flat, whereas the cells in the cross section were not flat.

Explanation:

The epidermis is made up of five cell layers, which have different functions: Stratum basale, stratum spinosum, stratum granulosum, stratum lucidum, and stratum corneum.

Stratum basale is the innermost germinative, single, basal layer of the epidermis composed of basal cuboidal-shaped cells. These cells are the precursor of keratinocytes, this is why this layer is also called germinativum. In this basal layer, there are also Merkel cells as well as melanocytes.

Stratum spinosum refers to the keratinocytes which produce keratin.

Stratum granulosum, this is the layer where keratinization begins. Cells produce hard granules that change to keratin and lipids as they ascend.

Stratum lucidum is conformed of densely compressed cells, which begins to flatten and appear indistinguishable between each other.

Stratum corneum is the most external layer, composed of dead, flattened cells which are released regularly in a process known as desquamation.

8 0

4 years ago

The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A

ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

Genotype Observed frequency

A → 18 individuals

B → 55 individuals

C → 27 individuals

Do these contradict the genetic model?

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.

Explanation:

Available data:

Crossed genotypes: two
Genotypes among the offspring; Three → A, B, and C
Expected phenotypic ratio → 1:2:1
Total number of individuals, N = 100
A = 18 individuals
B = 55 individuals
C = 27 individuals

So, let us first state the hypothesis:

H₀= the population is equilibrium for this locus → F(A) = 25%, F(B) = 50%, F(C) = 25%
H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 --------------- 25% -------------X = 25 individuals A

2 -------------- 50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

A B C

Observed 18 55 27
Expected 25 50 25
(Obs-Exp)²/Exp 1.96 0.5 0.16

(Obs-Exp)²/Exp

A) (18 - 25)²/25 = 49/25 = 1.96

B) (55 - 50)² / 50 = 25/50 = 0.5

C) (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp

∑ is the sum of the terms
O are the Observed individuals: 2 in chamber B, and 18 in chamber A.
E are the Expected individuals: 10 in each chamber

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99

These results suggest that there is not enough evidence to reject the null hypothesis. We can assume that the locus under study in this population is in equilibrium H-W.

6 0

3 years ago