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andriy [413]
3 years ago
12

Luara is 5 years older than her sister Elisabeth. She figured out that in 4 years she will be two times older than Elisabeth. Ho

w old are they now?
Mathematics
2 answers:
VladimirAG [237]3 years ago
6 0

laura is 9 and elizabeth is 4

RideAnS [48]3 years ago
5 0
She is 9 other one is 4
You might be interested in
The sequence 2, 3, 5, 6, 7, 10, … consists of
Kay [80]

The 76th term is 86.

<h3>What is sequence?</h3>

A sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members (also called elements, or terms). The number of elements (possibly infinite) is called the length of the sequence.

Given:

2, 3, 5, 6, 7, 10, …

The sequence consists of all natural numbers which are neither perfect squares nor perfect cubes.

We can as well sum the number of squares and cubes in the range with the number of the required term i.e

Number of squares = 8 ( 4,9,16,25,36,49,64,81)

Number of cubes = 2 (8 and 27; excluding 64 which is as well a square)

Required term = 75

So, 8+2+75 = 85.

Hence, the 85th term counting from 2 ( i.e 86) is the 75th term.

Learn more about sequence here:

brainly.com/question/16614966

#SPJ1

3 0
2 years ago
Could you answer the circled one for me because I got it wrong and I'm struggling. thanks
kompoz [17]
The answer should be 384.
Sorry if it's wrong.
6 0
3 years ago
United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res
Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so n = 200.

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So \pi = 0.0995.

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find P(X < 18), with \pi = 0.0995, n = 200. We can use a binomial probability calculator, and we find that:

P(X < 18) = 0.2927.

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

5 0
3 years ago
Please answer ASAAAAP get it right no I’ll give brainliest!
xz_007 [3.2K]

Answer:

The answer 175 3/4 me compadre

7 0
3 years ago
Help please please i give bralienst don't need to explain just put the number
klasskru [66]

Answer:

487 ÷ 14

Hope that helps.

6 0
3 years ago
Read 2 more answers
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