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frozen [14]
4 years ago
5

100 POINTSPLEASE PROVIDE STEPS. FOR BOTH FIND THE INTEGRALS

Mathematics
2 answers:
ryzh [129]4 years ago
8 0

Question 8:

∫sinxcos²xdx

∫-u²du <em>(let u = cos(x))</em>

-∫u²du

-u(^2+1)/2+1

-cos^(2+1)(x)/2+1

-1/3cos³(x)

-1/3cos³(x) + C

Question 9:

∫(secxtanx + eˣ)dx

∫sec(x)tan(x)dx + ∫eˣdx <em>(apply sum rule)</em>

sec(x) + eˣ <em>(sec(x)tan(x)dx = sec(x) and eˣdx = eˣ)</em>

sec(x) + eˣ + C

Best of Luck!

Lady_Fox [76]4 years ago
4 0

Answer:

8. -⅓ cos³x + C

9. sec x + eˣ + C

Step-by-step explanation:

8. ∫ sin x cos²x dx

If u = cos x, then du = -sin x dx.

∫ -u² du

-⅓ u³ + C

-⅓ cos³x + C

9. ∫ (sec x tan x + eˣ) dx

∫ sec x tan x dx + ∫ eˣ dx

These are both standard integrals:

sec x + eˣ + C

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If these are in exponent form -- the answer would be 2.01 x 10^{15} > 2.8 x 10.3

Step-by-step explanation:

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Step-by-step explanation:

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svetlana [45]

Answer:

A: This polynomial has a degree of 2 , so the equation 12x2+5x−2=0 has two or fewer roots.

B: The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots.

Step-by-step explanation:

f(x) = 12x^2 + 5x - 2.

Since this is a quadratic equation, or a polynomial of second degree, one can easily conclude that this equation will have at most 2 roots. At most 2 roots mean that the function can have either 2 roots at maximum or less than 2 roots. Therefore, in the A category, 2nd option is the correct answer (This polynomial has a degree of 2 , so the equation 12x^2 + 5x − 2 = 0 has two or fewer roots).

To find the roots of f(x), set f(x) = 0. Therefore:

12x^2 + 5x - 2 = 0. Solving the question using the mid term breaking method shows that 12*2=24. The factors of 24 whose difference is 5 are 8 and 3. Therefore:

12x^2 + 8x - 3x - 2 = 0.

4x(3x + 2) -1(3x+2) = 0.

(4x-1)(3x+2) = 0.

4x-1 = 0 or 3x+2 = 0.

x = 1/4 or x = -2/3.

It can be seen that f(x) has two distinct real roots. Therefore, in the B category, 1st Option is the correct answer (The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots)!!!

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