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frozen [14]
3 years ago
5

100 POINTSPLEASE PROVIDE STEPS. FOR BOTH FIND THE INTEGRALS

Mathematics
2 answers:
ryzh [129]3 years ago
8 0

Question 8:

∫sinxcos²xdx

∫-u²du <em>(let u = cos(x))</em>

-∫u²du

-u(^2+1)/2+1

-cos^(2+1)(x)/2+1

-1/3cos³(x)

-1/3cos³(x) + C

Question 9:

∫(secxtanx + eˣ)dx

∫sec(x)tan(x)dx + ∫eˣdx <em>(apply sum rule)</em>

sec(x) + eˣ <em>(sec(x)tan(x)dx = sec(x) and eˣdx = eˣ)</em>

sec(x) + eˣ + C

Best of Luck!

Lady_Fox [76]3 years ago
4 0

Answer:

8. -⅓ cos³x + C

9. sec x + eˣ + C

Step-by-step explanation:

8. ∫ sin x cos²x dx

If u = cos x, then du = -sin x dx.

∫ -u² du

-⅓ u³ + C

-⅓ cos³x + C

9. ∫ (sec x tan x + eˣ) dx

∫ sec x tan x dx + ∫ eˣ dx

These are both standard integrals:

sec x + eˣ + C

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