Answer:
<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.
Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:
n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).
So, n can be written as 3 times another integer, thus n is divisible by 3.
<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.
Assume that n is divisible by 3. The above proof suggest that we write it as
n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).
As k, k+1, k+2 are three consecutive integers, we have completed our goal.
Step-by-step explanation:
Answer:
Step-by-step explanation:
-5(2x - 5) = 8 + (5 - 2x)
-10x + 25 = 8 + 3x
-10x - 3x = 8 - 25
-13x = -17
<u>x</u><u> </u><u>=</u><u> </u><u>1</u><u>7</u><u>/</u><u>1</u><u>3</u><u> </u><u>=</u><u> </u><u>1</u><u> </u><u>4</u><u>/</u><u>1</u><u>3</u>
Answer:
2.2
Step-by-step explanation:
11÷5 because 20 goes into 100 5 tines hope this helps!:)
