I am not 100% sure on this one on this one

Mathematics

2 answers:

Troyanec [42]4 years ago

6 0

The laws of logarithms are comparable to the laws of exponents. By the laws of logarithms, log(a/b) = log(a) - log(b), as long as the bases between all the terms are consistent. Therefore, in this case, log_3 (d/12) = log_3 (d) - log_3 (12). This is the third of the choices.

Neporo4naja [7]4 years ago

4 0

Log(a/b) = loga - logb

log(d/12) = logd - log12

third option

You might be interested in

How to calculate 3x^2+14x+8=

Arada [10]

3x² + 14x + 8
3x² + 12x + 2x + 8
3x(x) + 3x(4) + 2(x) + 2(4)
3x(x + 4) + 2(x + 4)
(3x + 2)(x + 4)

3 0

3 years ago

Math Write the number 63 in four different ways.

Rina8888 [55]

63 = 0.63×10² = 126/2 = 3×21 = √3969 = 77₈

The last is as a base-8 number.

5 0

4 years ago

Read 2 more answers

suppose you have ab on a coordinate plane located at a(-3,-4) and b(5,-4). under a dilation centered at (9,0), ab becomes a'b' w

Galina-37 [17]

The distace between the center of dilation and point a is diven by:

$d=\sqrt{(9-(-3))^2+(0-(-4))^2} \\ \\ =\sqrt{(9+3)^2+(0+4)^2}=\sqrt{12^2+4^2} \\ \\ =\sqrt{144+16}=\sqrt{160}=\sqrt{16\times10}=4\sqrt{10}$

The distance between the center of dilation and point a' is given by:

$d=\sqrt{(9-6)^2+(0-(-1))^2} \\ \\ =\sqrt{3^2+(0+1)^2}=\sqrt{3^2+1^2} \\ \\ =\sqrt{9+1}=\sqrt{10}$

It can be seen that the distance from the center of dilation to the image is 1/4 times the distance from the centre of dilation to the preimage.

Therefore, the scale factor is 1/4.

7 0

4 years ago

(64/25)^-1/2 Give your answer as a fraction in it's simplest form.

scoray [572]

5/8

Mark brainliest please

Hope this helps you

5 0

3 years ago

Plz help correct answer gets brainliest.

Leona [35]

whats the question?????

3 0

3 years ago

Read 2 more answers