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Ugo [173]
2 years ago
7

1. Solve 17 - x = 1 + 3x

Mathematics
2 answers:
Verdich [7]2 years ago
5 0

Answer:

x = 4

Step-by-step explanation:

1) Add x to both sides.

17 = 1 + 3x + x

2) Simplify 1 + 3x + x to 1 + 4x.

17 = 1 + 4x

3) Subtract 1 from both sides.

17 - 1 = 4x

4) Simplify 17 - 1 to 16.

16 = 4x

5) Divide both sides by 4.

\frac{16}{4}  = x

6) Simplify 16/4 to 4.

4 = x

7) Switch sides.

x = 4

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u>.

timurjin [86]2 years ago
4 0
X = 8

We’ll combine like terms by getting all the x terms on the right, all the digits on the left.

16 = 2x
Divide both sides by 2
x = 8
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4 0
3 years ago
A boy throws a ball into the air. The equation h=−16t^2+23t+4 models the path of the ball, where h is the height (in feet) of th
lina2011 [118]

Answer:

0.72secs

Step-by-step explanation:

Given the height of the ball in air modeled by the equation:

h=−16t²+23t+4

Required

Total time it spent in the air

To get this we need to calculate its time at the maximum height

At the maximum height,

v = dh/dt = 0

-32t + 23 = 0

-32t = -23

t = 23/32

t = 0.72secs

<em>Hence the total time it spend in the air will be 0.72secs</em>

8 0
3 years ago
Does anyone know this need help
madreJ [45]

Answer:

32 m

Step-by-step explanation:

The distance across the river is give as x and we are interested in finding the value of x.

Both the triangles are similar by AA Postulate.

Therefore,

20/x = 10/16 (by c.s.s.t.)

2/x = 1/16

x = 16*2

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8 0
3 years ago
What is log b^b^6x equivalent to (The b is under log and ^b)? How do you know?
Arturiano [62]

Answer: 6x

Work Shown:

For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that \log_b(b) = 1 meaning that the log base of itself is 1

log(b^(6x)) = 6x*log(b) .... pull down exponent using the first rule above

log(b^(6x)) = 6x*1 .... use the second rule mentioned

log(b^(6x)) = 6x

4 0
3 years ago
Please solve this simultaneous equation, i'm not that good at it.<br><br> 2r-s=10<br> rs-s^2=12
o-na [289]

Answer:

s = 6, r = 8 or s = 4, r = 7

Step-by-step explanation:

2r - s = 10

2r = 10 + s

r = 5 + s/2 --(1)

rs - s^2 = 12 --(2)

sub (1) into (2):

(5 + s/2)s - s^2 = 12

5s + 0.5s^2 - s^2 = 12

-0.5s^2 + 5s - 12 = 0

s^2 - 10s + 24 = 0

(s - 6)(s - 4) = 0

therefore s = 6 or s = 4

when s = 6, r = 8 and when s = 4, r = 7

if you would like to discover more about simultaneous equations, you can have a look at my Instagram page (learntionary). I'll be posting mathematics related stuff there and some of my notes (simultaneous enq notes are already posted!)

7 0
2 years ago
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