Answer:
3
Step-by-step explanation:
6x+2y=12
2y=6x-12
y=6x/2- 12/2
y=3x-6
Answer:
556
Step-by-step explanation:
Surface area of the cuboid=2*(lb+bh+lh)
Surface area=2*(110+80+88)=556
<span>Simplifying
(5b + -9) + -3(8 + -2b) = 0
Reorder the terms:
(-9 + 5b) + -3(8 + -2b) = 0
Remove parenthesis around (-9 + 5b)
-9 + 5b + -3(8 + -2b) = 0
-9 + 5b + (8 * -3 + -2b * -3) = 0
-9 + 5b + (-24 + 6b) = 0
Reorder the terms:
-9 + -24 + 5b + 6b = 0
Combine like terms: -9 + -24 = -33
-33 + 5b + 6b = 0
Combine like terms: 5b + 6b = 11b
-33 + 11b = 0
Solving
-33 + 11b = 0
Solving for variable 'b'.
Move all terms containing b to the left, all other terms to the right.
Add '33' to each side of the equation.
-33 + 33 + 11b = 0 + 33
Combine like terms: -33 + 33 = 0
0 + 11b = 0 + 33
11b = 0 + 33
Combine like terms: 0 + 33 = 33
11b = 33</span>
Answer:
The height of the pole is 167 m
Step-by-step explanation:
The given parameters are;
Increase in the length of the shadow = 90 m
Initial angle of elevation of the Sun = 58°
Final angle of elevation of the Sun = 36°
We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase in the length of the shadow
We have by sin rule;
90/(sin (22°) = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)
Let the initial ray from the top of the pole to the end of the shadow's length = l₁
90/(sin (22°) = l₁/(sin(122°)
l₁ = 90/(sin (22°) ×(sin(122°) = 283.3 m
Therefore;
The height of the pole = 283.3 m × sin(36°) = 166.52 m
The height of the pole= 167 m to three significant figures.
She has 3.878 miles left to hike. (439/500 in fraction form)