First things first you have to do write it down which you did
step 2: then you multiply each digit of the binary number by the corresponding power of 2: 1x25 + 0x24 + 1x23 + 1x22 + 0x21 + 1x2 0
step 3: solve the powers: 1x32 + 0x16 + 1x8 + 1x4 + 0x2 + 1x1 = 32 + 0 + 8 + 4 + 0 + 1
step 4: add the numbers written above
32 + 0 + 8 + 4 + 0 + 1 = 45.
So, 45 is the decimal equivalent of the binary number 101101.
On a rheostat the first terminal is connected to a
A ground return path
fined contact
Ceramic heat sink
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A. number of addresses is 65536
b. memory capacity is 128 kbytes or 131072 bytes
c. The last memory address is FFFF which is 65535
Answer:
Following are the code block in the Java Programming Language.
//define recursive function
public static long exponentiation(long x, int n) {
//check the integer variable is equal to the 0.
if (x == 0) {
//then, return 1
return 1;
}
//Otherwise, set else
else {
//set long data type variable
long q = exponentiation(x, n/2);
q *= q;
//check if the remainder is 1
if (n % 2 == 1) {
q *= x;
}
//return the variable
return q;
}
}
Explanation:
<u>Following are the description of the code block</u>.
- Firstly, we define the long data type recursive function.
- Then, set the if conditional statement and return the value 1.
- Otherwise, set the long data type variable 'q' that sore the output of the recursive function.
- Set the if conditional statement and check that the remainder is 1 and return the variable 'q'.
