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WINSTONCH [101]
3 years ago
14

You wrote a program to find the factorial of a number. In mathematics, the factorial operation is used for positive integers and

zero.
What does the function return if the user enters a negative three?

def factorial(number):
product = 1
while number > 0:
product = product * number
number = number - 1
return product

strNum = input("Enter a positive integer: ")
num = int(strNum)
print(factorial(num))


-6

1

There is no output due to a runtime error.

-3
Computers and Technology
2 answers:
Alona [7]3 years ago
7 0

Answer: 1

Explanation:

got it on Edge.

Nata [24]3 years ago
3 0

Answer:

The correct answer is 1

Explanation:

Correct on edge 2020

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. Write a function called is_sorted that takes a list as a parameter and returns True if the list is sorted in ascending order a
aalyn [17]

Answer:

There are multiple ways to solve the given problem, I will be presenting the most simple and easy way of solving this problem in few lines of code.

Python code:

def is_sorted(user_list):

   return user_list == sorted(user_list)

user_list=input("Please enter a list: ")

user_list = user_list.split()

print(is_sorted(user_list))

print("Your list: ", user_list)

Explanation:

A function is_sorted is created which takes a list as input and using the sorted() function of python which returns true when the list is sorted in ascending order and returns false when the list is not sorted in ascending order.

Driver code includes getting input list from the user and using split() function to create a list separated by space then printing the output of is_sorted function and in the last printing the contents of that list.

Output:

Please enter a list: 1 3 6 9

True

Your list:  ['1', '3', '6', '9']

Please enter a list: 15 7  2 20

False

Your list:  ['15', '7', '2', '20']

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3 years ago
Edhesive intro to cs term 2 8.9 practice
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Suppose you are an ad-serving company and you maintain a log of cookie data for ads you serve to the Web pages for a particular
Firlakuza [10]

Answer:

A

Explanation:

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3 0
2 years ago
Create an array of 7 words,named "temperatures"containing daily temperatures for a week. Temperatures can be positive or negativ
zepelin [54]

Answer:

// program in C++.

// headres

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // array

   int temperatures[7];

   // count variable

   int count=0;

   cout<<"Enter the temperature of all days:";

   for(int a=0;a<7;a++)

   {

       // read temperature of 7 days

       cin>>temperatures[a];

       // find temperature is extreme or not

       if(temperatures[a]<-10||temperatures[a]>25)

       // count

       count++;

   }

   // print count of extreme temperature

   cout<<"number of days of extreme temperature:"<<count<<endl;

return 0;

}

Explanation:

Create an array of size 7 to store the temperature of all days of week.Read the temperature of each day.If the temperature is less than -10 or greater than 25 then increment the count.This will count the number of days of extreme temperature.Print  the count.

Output:

Enter the temperature of all days:-20 12 18 30 32 -15 15                                                                  

number of days of extreme temperature:4

3 0
3 years ago
Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr
drek231 [11]

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

#include <cmath>  // to use math functions like sqrt()

#include <iomanip>  //to use setprecision method

using namespace std;   //to access objects like cin cout

int main ()  {  //start of main function

  double speedA;  //double type variable to store average speed of car A

  double speedB;  //double type variable to store average speed of car B

  int hour;  //int type variable to hold hour part of elapsed time

  int minutes;  //int type variable to hold minutes part of elapsed time

  double shortDistance;  // double type variable to store the result of shortest distance between car A and B

  double distanceA;  //stores the distance of carA

  double distanceB;  //stores the distance of carB

  double mins,hours;   //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl;  //prompt user to enter the average speed of car A

cin >> speedA;   //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ;  //prompt user to enter the average speed of car B

cin >> speedB;   //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl;  //prompts user to enter elapsed time

cin>> hour >> minutes;    //reads elapsed time in hours and minutes

  mins = hour * 60;  //computes the minutes using value of hour

  hours = (minutes+mins)/60;     //computes hours using minutes and mins

distanceA = speedA * (hours);  // computes distance of car A

distanceB = speedB * (hours);   //computes distance of car B

   shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB));   //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;  

This becomes

mins = 2 * 60

mins = 120

Next

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

         = 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);  

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

                        = sqrt(30625 + 18906.25)

                        = sqrt(49531.25)

                        =  222.556173

shortDistance =  222.56

 

Hence the output is:

The (shortest) distance between the cars is: 222.56        

3 0
3 years ago
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