Answer:
y = 148°
Step-by-step explanation:
4x - 18 = 2x + 12 (alternate exterior angles are congruent)
Collect like terms
4x - 18 = 2x + 12
4x - 2x = 18 + 12
2x = 20
Divide both sides by 2
x = 10
y = 180 - (2x + 12) (linear pair theorem)
Plug in the value of x
y = 180 - (2(10) + 12)
y = 180 - (20 + 12)
y = 148°
Answer:
None
Step-by-step explanation:
It would be easier to ask your teacher instead of getting wrong answers from random people. Ever think of that :0
Answer:
The value of the snack bar is $ 2 and that of the magazine subscription is 25 $
Step-by-step explanation:
We have a system of two equations and two unknowns, which would be the following:
let "x" be the cost of the snack bar
Let "y" be the cost of the magazine subscription
16 * x + 4 * y = 132
20 * x + 6 * y = 190 => y = (190 - 20 * x) / 6
replacing:
16 * x + 4 * (190 - 20 * x) / 6 = 132
16 * x + 126.66 - 13.33 * x = 132
2.66 * x = 132 - 126.66
x = 5.34 / 2.66
x = 2
for "y":
y = (190 - 20 * 2) / 6
y = 25
Which means that the value of the snack bar is $ 2 and that of the magazine subscription is 25 $
The position function of a particle is given by:
The velocity function is the derivative of the position:
The particle will be at rest when the velocity is 0, thus we solve the equation:
The coefficients of this equation are: a = 2, b = -9, c = -18
Solve by using the formula:
![t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Substituting:
![\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81-4%282%29%28-18%29%7D%7D%7B2%282%29%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81%2B144%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B225%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm15%7D%7B4%7D%20%5Cend%7Bgathered%7D)
We have two possible answers:
We only accept the positive answer because the time cannot be negative.
Now calculate the position for t = 6:
