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3 years ago

NEED HELP FOR A CHAPTER REVIEW TOMORROW!!! Name the points. Thank you!!!!

Mathematics

1 answer:

Stella [2.4K]3 years ago

8 0

It’s and equation stating the fact that the answer is 21

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Can someone answer questions 20-24 I need it for my math homework

navik [9.2K]

You know you have to draw the triangles right?

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2 years ago

Mark practices his guitar 3/4 hours each day. How many hours does he practice in seven days?

Mashutka [201]

3/4 *7
or
0.75*7
The answer is 5.25

6 0

3 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

3 0

3 years ago

ILL MARKE BRAINLIEST IF YOU SHOW YOUR WORK

madam [21]

The function of the relationship above is y=5x+4

4 0

3 years ago

Three balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the cylin

lianna [129]

We know the following:
Cylinder volume: V₁ = π r² h
Ball (sphere) volume:V₂ = $\frac{4}{3}$ π r³
where:
V - volume
r - radius of base of cylinder and diameter of ball
h - height of cylinder.

R = 13 cm ⇒ r = 13 ÷ 2 = 6.5
π = 3.14

a) Since balls touch all sides of cylinder (as shown in image), it can be concluded that height of cylinder is equal to sum of diameters of 3 balls and that radius of base of cylinder is equal to radius of ball:
h = 3 × r = 3 × 13 cm = 39 cm
r = 6.5 cm
So,
V₁ = π r² h
V₁ = 3.14 × (6.5 cm)² × 39 cm
V₁ = 5,173.9 cm³

b. The total volume of three balls is the sum of volumes of each ball:
Vₐ = 3 × V₂
Vₐ = 3 × $\frac{4}{3}$ π r³
Vₐ = 3 × $\frac{4}{3}$ 3.14 (6.5 cm)³
Vₐ = 3,449.3 cm³

c. Percentage of the volume of the container occupied by three balls ould be expressed as ratio of volume of three balls and volume of cylinder:
V = $\frac{ V_{1}}{ V_{a} }$ ×100
V = $\frac{3,449.3}{5,173.9}$ ×100
V = 0.6666 ×100
V = 66.66%

4 0

2 years ago

Read 2 more answers