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AlexFokin [52]
3 years ago
13

Solve for w solve for x solve for y

Mathematics
2 answers:
Minchanka [31]3 years ago
6 0

Answer:

w = 58°

x = 32°

y = 16°

Step-by-step explanation:

The triangle on the bottom is an isosceles triangle. They have two equal sides, which we know because two of the sides have a little tick through them.

All isosceles triangles have two equal angles that are not angle contained by the equal sides.

All triangles' interior angles add to 180°.

Using properties of triangles and isosceles triangles, we can find w.

64° + 2w = 180°

2w = 116°

w = 58°

The angle opposite to w is also 58°.

About that right angle, represented by a square: all right angles are 90°. This property is called complementary angles, meaning angles that add to 90°.

That angle is made of 58° + x.

58° + x = 90°

x = 32°

For the triangle on the left, it has an angle that connects to the 64°. Because it forms a straight line with the other angle, it adds to 180°. This property is called supplementary angles. That angle + 64° is 180°.

I will label it "a".

a + 64° = 180°

a = 116°

To find angle 2y, use the property where a triangles' angles add to 180°.

a + x + 2y = 180°

We already know "a" and "x", so we can substitute those values.

116° + 32° + 2y = 180°

2y = 32°

y = 16°

Summary of properties used:

All triangles' interior angles add to 180°

Isosceles triangles have two equal sides and two equal angles

Right angles add to 90°, called complementary angles

Straight lines add to 180°, called supplementary angles

Anna007 [38]3 years ago
4 0

Answer:

w = 58°

x = 32°

y = 16°

Step-by-step explanation:

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castortr0y [4]

Answer:

½ sec²(x) + ln(|cos(x)|) + C

Step-by-step explanation:

∫ tan³(x) dx

∫ tan²(x) tan(x) dx

∫ (sec²(x) − 1) tan(x) dx

∫ (sec²(x) tan(x) − tan(x)) dx

∫ sec²(x) tan(x) dx − ∫ tan(x) dx

For the first integral, if u = sec(x), then du = sec(x) tan(x) dx.

∫ u du = ½ u² + C

Substituting back:

½ sec²(x) + C

For the second integral, tan(x) = sin(x) / cos(x).  If u = cos(x), then du = -sin(x) dx.

∫ -du / u = -ln(u) + C

Substituting back:

-ln(|cos(x)|) + C

Therefore, the total integral is:

½ sec²(x) + ln(|cos(x)|) + C

4 0
3 years ago
an airplane 30000 feet above the ground begins descending at a rate of 2000 feet per minute. write an equation to model the situ
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4 years ago
Round each number to the nearest ten. What is the best estimate for the answer to 343.42 – 39.87?
Nikolay [14]
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Hope it helped you
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4 years ago
What is the factored form of m2 + - 27n2
Illusion [34]
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3 0
3 years ago
Table:
Fynjy0 [20]

Answer:

2) Yes, each x-coordinate is only used once.

3) {1,2,3,4}

4) {25,45,60,70}

5) (3,60)

6) No because (4,7) and (4,25) share the same x-coordinate.

Step-by-step explanation:

A relation is a function if there is no more than one y-value assigned to an x.

Any x used can only be used once in an order pair.

You that here.

(1,25)

(2,45)

(3,60)

(4,70)

So basically because all of the x-coordinates are different, this is a function.

The domain is the x-coordinate of each pair (the first of each pair):

{1,2,3,4}.

The range is the y-coordinate of each pair (the second number of each pair):

{25,45,60,70}.

One ordered pair that I see in the table is (3,60). There are 3 others you can choose and I named them above.

{(4,10),(3,15),(1,5),(2,25),(4,25)} is not a function because there are more than one pairs with the same x-coordinate,4.  

3 0
4 years ago
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