Answer: the incubation time that separates the bottom 2.5% from the rest of the incubation times is 24.96 days.
Step-by-step explanation:
Suppose the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = incubation times.
µ = mean time
σ = standard deviation
From the information given,
µ = 23 days
σ = 1 day
The probability value for the incubation time that separates the bottom 2.5% from the rest of the incubation times would be (1 - 2.5/100) = (1 - 0.025) = 0.975
Looking at the normal distribution table, the z score corresponding to the probability value is 1.96
Therefore,
1.96 = (x - 23)/1
x = 1.96 + 23
x = 24.96
I think the answer is a or d not sure
Answer:
im guessing 244 because i think 331 is the real value?
Step-by-step explanation:
331-87=244
V = L x W x H
V = (2/3 x 5/6) x 4/5
V = 5/9 x 4/5
V = 4/9
Therefore, your answer is v = 4/9 yards cubed
Answer:
8:7
Step-by-step explanation:
