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ludmilkaskok [199]
3 years ago
6

What is 2/5 of 26 ?

Mathematics
1 answer:
grandymaker [24]3 years ago
4 0
2/5 × 26 equals 10.4
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What is the circumference of the circle in terms of pi with a radius of 10in
o-na [289]

ANSWER

EXPLANATION

The circumference of a circle is calculated using the formula:

C=2\pi \: r

From the question, the radius of the circle is 10 inches.

We substitute the radius into the formula to get:

C=2\pi \times 10

Let us multiply out to get:

C=20 \pi \: in

The question required that we leave the answer in terms of π.

The correct choice is C.

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3 years ago
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Answer:

  • The angles do not share a special relationship.

Step-by-step explanation:

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Select the measurement that is most reasonable
Natalija [7]
I think it might be A
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3 years ago
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(07.05) Which of these is a simplified form of the equation 7x + 4 = 5 + 3x + 1x? (4 points) 3x = 9 3x = 1 11x = 9 11x = 1
slava [35]
Okay first you need to combine like terms together (3x and 1x)

7x + 4 = 5 + 4x

now you need x only on one side, you could subtract either 7x or 4x 

3x + 4 = 5

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4 0
3 years ago
The mass of a dust particle is approximately
trasher [3.6K]

Answer:

Given:

  • \textsf{Mass of a dust particle} = \sf 7.5 \times 10^{-10}
  • \textsf{Mass of an electron} = \sf 9.1 \times 10^{-31}

To calculate how many electrons have the same mass as one dust particle, divide the mass of a dust particle by the mass of an electron:

\begin{aligned}\implies \dfrac{\textsf{Mass of a dust particle}}{\textsf{Mass of an electron}} & = \sf \dfrac{7.5 \times 10^{-10}}{9.1 \times 10^{-31}}\\\\& = \sf \dfrac{7.5}{9.1} \times \dfrac{10^{-10}}{10^{-31}}\\\\& = \sf 0.8241... \times 10^{(-10-(-31))}\\\\& = \sf 0.8241... \times 10^{21}\\\\& = \sf 8.2 \times 10^{20}\end{aligned}

Therefore, approximately \sf 8.2 \times 10^{20} electrons have the same mass as one dust particle.

8 0
2 years ago
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