n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
2.8 m = .0028 km
3.5/.0028 = 1259 revolutions
Answer:
r = 10 cm
Step-by-step explanation:
r² = 8² + 6²
r² = 64 + 36 = 100
r = 10 cm
Step-by-step explanation:
For every increase in the x-value by 1,
the y-value decreases by -2.
(From 3 to 1 and from 1 to -1)
Hence, slope of line k
= Rise/Run = (-2)/1 = -2. (A)
Given your ordered pair you would assume a = 5, b = 2
Set up both equations
5 + 2 = 7
7 = 7 (the numbers are equal so this correct)
2(5) - 8 = 2
10 - 8 = 2
2 = 2 (the numbers are equal so this is also correct)
Because both equations work with the ordered pair they <em>are</em><span> the solution of the given system.</span>
