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3 years ago

The area of a square carpet tile is 900 square centimeters. What is the length of one edge of the tile in centimeters

1 answer:

8 0

Let the side of one edge of tile = a cm.

So area of tile = (side)^2 = $a^2$

But area of tiles = 900 square centimeter.

So $a^2 = 900$

$a = \sqrt{900}$
$= 30$

So side of one edge of tile is = 30 cm

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Solve the quadratic equation by completing the square. 6x2 + 4x - 5 = 0

Nikitich [7]

Answer:

$x_{1}=-\frac{2+\sqrt{34}}{6}$

$x_{2}=-\frac{2-\sqrt{34}}{6}$

Step-by-step explanation:

Quadratic Equation given:

$6x^2 + 4x - 5 = 0$

Start dividing both sides by 6.

$\frac{6}{6} x^2 +\frac{4}{6} x - \frac{5}{6} = \frac{0}{6}$

$x^2 +\frac{2}{3} x - \frac{5}{6} = 0$

$x^2 +\frac{2}{3} x = \frac{5}{6}$

Once, $\left( \frac{2}{3} \cdot \frac{1}{2} \right)^2=\frac{1}{9}$

$x^2 +\frac{2}{3} x+\frac{1}{9} = \frac{5}{6}+\frac{1}{9}$

$\left(x+\frac{1}{3} \right)^2 = \frac{17}{18}}$

$x+\frac{1}{3} =\pm\sqrt{\frac{17}{18}} }$

Solving $\sqrt{\frac{17}{18}}$

$\sqrt{\frac{17(18)}{18(18)}}= \sqrt{\frac{306}{324}}=\frac{3\sqrt{34} }{18} =\frac{\sqrt{34} }{6}$

Then,

$x+\frac{1}{3} =\pm\frac{\sqrt{34} }{6}$

$x =-\frac{1}{3} \pm\frac{\sqrt{34} }{6}$

$x_{1}=-\frac{2+\sqrt{34}}{6}$

$x_{2}=-\frac{2-\sqrt{34}}{6}$

6 0

3 years ago

WILL GIVE BRAINLIEST!!!!!!!

lara [203]

Paralell has same slope
slope of ax+by=c is -a/b
so a paralalell line to ax+by=c is ax+by=z where a=a and b=b and z is a constant

so
paralalel to 3x-2y=-6 is 3x-2y=?
find ?
given point (4,2)
sub
3(4)-2(2)=12-4=8

equation is 3x-2y=8
solving for slope itnercept or y
minus 3x both sides
-2y=-3x+8
divide by -2
y=3/2x-4

B is answer

8 0

3 years ago

An advertising agency that serves a major radio station wants to estimate the mean amount of time the station’s audience members

Flura [38]

Answer:

$n=(\frac{1.645(45)}{5})^2 =219.18 \approx 220$

So the answer for this case would be n=220 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\sigma = 45$ represent the population deviation

$ME = 5$ represent the margin of error

The margin of error for the true mean is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (4) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 90% of confidence interval now can be founded using the normal distribution. The significance level is $\alpha=1-0.9=0.1$ and the critical value would be $z_{\alpha/2}=1.645$ , replacing into formula (b) we got: