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katen-ka-za [31]
4 years ago
5

PLEASE HELP ASAP Which of the following are irrational?

Mathematics
2 answers:
steposvetlana [31]4 years ago
7 0
The answers b and p are irrational

IrinaVladis [17]4 years ago
3 0
Answer: B and P


Hope that helps



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G(t)=−(t−1)^2+5
garri49 [273]

Answer:

In the interval of - 2 ≤ t ≤ 4, the average rate of change is zero.

Step-by-step explanation:

The function is given to be g(t) = - (t - 1)^{2} + 5  ............ (1)

(i) Now, for 1 ≤ t ≤ 4, we will put t = 1 and t = 4.

So, g(1) = 5, g(4) = - 4.  {From equation (1)}

Hence, g(1) ≠ g(4)

(ii) Now, for - 4 ≤ t ≤ - 3, we will put t = - 4 and t = - 3.

So, g(- 4) = - 20, g(- 3) = - 11.  {From equation (1)}

Hence, g(- 4) ≠ g(- 3)

(iii) Now, for -2 ≤ t ≤ 0, we will put t = - 2 and t = 0.

So, g(- 2) = - 4, g(0) = 4.  {From equation (1)}

Hence, g(- 2) ≠ g(0)

(iv) Now, for - 2 ≤ t ≤ 4, we will put t = - 2 and t = 4.

So, g(- 2) = - 4, g(4) = - 4.  {From equation (1)}

Hence, g(- 2) = g(4)

Therefore, in the interval of - 2 ≤ t ≤ 4, the average rate of change is zero. (Answer)

5 0
4 years ago
A right circular cylinder has a height of ​ 19 3/4 ​ ft and a diameter ​ 1 2\5 ​ times its height.
alexira [117]

Answer:

Volume of cylinder is  34833.21 ft³

Step-by-step explanation:

Given : A right circular cylinder having height 19\frac{3}{4} ft and diameter \frac{12}{5} ​times its height.

Given : diameter \frac{12}{5} ​times its height that is

diameter \frac{12}{5} ​times  19\frac{3}{4}  that is

Diameter = \frac{12}{5} \times \frac{79}{4} ​

Diameter = \frac{237}{5} ft

Radius is half of diameter,

Radius = \frac{1}{2} \times \frac{237}{5}=\frac{237}{10} ft

\text{Volume of Cylinder}=\pi r^2h

Substitute the values, we get,

\text{Volume of Cylinder}= \pi (\frac{237}{10})^2 \times \frac{79}{4}

\text{Volume of Cylinder}= \times 3.14 \times (23.7)^2 \times 19.75

\text{Volume of Cylinder}= \times 3.14 \times (23.7)^2 \times 19.75

\text{Volume of Cylinder}=34833.21

Thus, volume of cylinder is  34833.21 ft³


6 0
3 years ago
Suppose that a die is rolled twice. What are the possible values that the following random variables can take on: (a) the maximu
Fiesta28 [93]

Answer:

See explanation

Step-by-step explanation:

Suppose that a die is rolled twice. Each time one of 6 numbers (1, 2, 3, 4, 5, 6) can be rolled.

A. the maximum value to appear in the two rolls is 6

B. the minimum value to appear in the two rolls is 1

C. the sum of the two rolls can vary from 2 to 12 (it can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

D. the value of the first roll minus the value of the second roll can very from -5 to 5 (-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5)

Here -5 can be obtained as 1 - 6 (1 on the first roll and 6 on thesecond roll), -4 can be obtained as 1 - 5 or 2 - 6 and so on.

3 0
3 years ago
Find both of the x values
gulaghasi [49]

3x - 14 = 2x + 25

      +14      +14

3x = 2x + 39

-2x     -2x

x= 39

therefore x is 39. If you want to find the exact angel, just substitute 39 into x, solve for it and it should give you the exact angel.

Hope I helped :)

8 0
4 years ago
Read 2 more answers
Is y= 2x cubed +6 linear or non-linear
zhuklara [117]
Non linear because nothing cubed or squared can be linear.
Hope this helps
6 0
3 years ago
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