The angle of the plane when it rose from the ground is 64.8 degrees
<h3>Application of trigonometry identity</h3>
Given the following parameters from the question
Altitude of the airplane H = 500m
Horizontal distance from airport "d" = 235
Required
angle of elevation
According to the trigonometry identity
tan x = opposite/adjacent
tan x = H/d
tan x = 500/235
tan x = 2.1277
x = arctan(2.1277)
x = 64.8 degrees
The angle of the plane when it rose from the ground is 64.8 degrees
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Answer:
Step-by-step explanation:
Given the Total revenue R(x) = 2x
Cost C(x) = 0.01x²+0.3x+30 where;
x = 30 and dx/dt = 9units per day.
Rate of change of revenue dR/dt = dR/dx • dx/dt
dR/dt = 2dx/dt
dR/dt = 2(9) = $18
Rate of change of revenue with respect to time is 18dollars/day.
Rate of change of cost dC/dt = dC/dx • dx/dt
dC/dt = (0.02x+0.3)dx/dt
dC/dt at x = 30 and dx/dt = 9 will give;
dC/dt = {0.02(30)+0.3}×9
dC/dt = (0.6+0.3) × 9
dC/dt = 0.9×9
dC/dt = $8.1
Rate of change of cost with respect to time is 8.1dollars/day
Profit = Revenue - Cost
Profit = 18-8.1
Daily Profit = $9.9
Answer:
2nd option
Step-by-step explanation:
- 5 = 
← in the form 
The answer is 78
If you multiply 17x6 you get 102
102 equals the whole rectangle after that you need to get rid of the part that’s not there
so you multiply 8x3 which equals 24
you then subtract 24 from 102 and get 78
Answer:
2 1/8
Step-by-step explanation:
-7/4 is equal to -14/8
14/8 plus 3/8 is 17/8
17/8 = 2 1/8
