Answer:

unit rate is similar to speed / velocity:

[<em>unit</em><em> </em><em>rate</em><em> </em><em>must</em><em> </em><em>have</em><em> </em><em>units</em><em> </em><em>including</em><em> </em><em>per</em><em> </em><em><</em><em>time</em><em>></em><em> </em>]
Answer:
it is 25 ft
Step-by-step explanation:
you just add 7.7+7.7+4.8+4.8 to get 25
Let point is(x,y)
x=(2-0)/5=2/5
y=(-6-5)/5=-11/5
(2/5,-11/5)
Answer:
p = 9 when q = 5.
Step-by-step explanation:
p is inversely proportional to the square of q
This means that:

In which k is a constant multiplier.
p is 25 when q is 3
We use this to find k.



So

Determine p when q is equal to 5.

p = 9 when q = 5.
14n + 21
Just distribute the 7 to the 2n and the 3.
7(2n + 3)
(7 * 2n) + (7 * 3)
14n + 21
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