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3 years ago

The sum of 5 consecutive even numbers is 200. what is the fifth number in this sequence

Mathematics

2 answers:

Andrej [43]3 years ago

8 0

Answer: 44

solution: x+(x+2)+(x+4)+(x+6)+(x+8)=200
5x+20=200
5x=180
x=36
5th number - x+8=36+8=44

Deffense [45]3 years ago

7 0

Answer:

The fifth number in this sequence is 44.

Step-by-step explanation:

Given : The sum of 5 consecutive even numbers is 200.

To find : What is the fifth number in this sequence?

Solution :

Let the 5 consecutive even numbers are x,(x+2),(x+4),(x+6),(x+8)

The sum of 5 consecutive even numbers is 200.

i.e. $x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 200$

Solving the equation,

$5x+20= 200$

$5x=180$

$x=\frac{180}{5}$

$x=36$

So, The numbers are

First number x=36

Second number x+2=36+2=38

Third number x+4=36+4=40

Fourth number x+6=36+6=42

Fifth number x+8=36+8=44

Therefore, The fifth number in this sequence is 44.

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Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

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