The median number of cars for both distributions lies in the 20–30 interval and there were more than 40 cars in line more often on the weekend then the weekday.
<h3>What is mean and median ?</h3>
The arithmetic mean is found by adding the numbers and dividing the sum by the number of data in the list.
The median is the middle value in a list ordered from smallest to largest.
Given data:
Data A:
0 - 10 4
10 - 20 13
20 - 30 19
30 - 40 8
40 - 50 5
50 - 60 1
Data B:
0-10 12
10-20 20
20-30 14
30-40 3
40-50 1
Thus, the median number of cars for both distributions lies in the 20–30 interval and there were more than 40 cars in line more often on the weekend then the weekday.
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We have that the graph will have a solution that is mathematically given as
y=12sin(6t-\pi)+2
<h3>
Daylight time June trough to December</h3>
Question Parameters:
A city averages 14 hours of daylight in June (the longest days) and 10 in December (the shortest days).
Generally the equation for the Amplitude and vertical shift is mathematically given as
A=2
vertical shift =
vertical shift =
vertical shift =1
Therefore, the time is given as
Where
Hence,The graph will have a solution
y=12sin(6t-\pi)+2
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Answer:
p=2x^3+3x
Step-by-step explanation:
no explanation math papa
Since the constant has been moved to the left side, you can move on to the next step which is adding (b/2)² to both sides of the equation.
h² + 14h + (14/2)² = -31 + (14/2)²
Simplify the parenthesis and exponent.
h² + 14h + 7² = -31 + 7²
h² + 14h + 49 = -31 + 49
h² + 14h + 49 = 18
Factor the expression of the left.
(h + 7)(h + 7) = 18
Take the square root of both sides.
√(h + 7)(h + 7) = ± √9 • 2
(h + 7) = ± 3√2
h + 7 = ± 3√2
Subtract 7 from both sides.
You solutions are:
h = -7 + 3√2 → -2.7573 → -2.76
h = -7 - 3√2 → -11.2426 → -11.24
The 2 triangles are congruent
