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3 years ago

The perimeter of a rhombus is 28 centimeters. What is the length of each side of the rhombus?

Mathematics

2 answers:

kenny6666 [7]3 years ago

8 0

All sides of a rhombus are congruent. 28/4 (four sides) =7

Each side is 7 cm long

Leni [432]3 years ago

4 0

Answer:

Each side is 7 cm long

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Find the diagonal of a square whose sides are of the given measure. Given = 16"

Olegator [25]

we are given the measurement of the side of a square equal to 16 inches. The square when divided into two using a diagonal forms a 45-45-90 angle. This means this follows the Pythagorean theorem in which the diagonal is square root of 2 times the length of the sides of the square. In this case, the diagonal measures then 16sqrt2 inches

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3 years ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

Veseljchak [2.6K]

Answer:

$1)\\\large\boxed{x=\dfrac{a+c}{b},\ if\ b\neq0}\\\\2)\\\boxed{if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number}\\\\\boxed{if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)}$

Step-by-step explanation:

$1)\\a-(a+b)x=(b-a)x-(c+bx)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\a-ax-bx=bx-ax-c-bx\qquad\text{cancel}\ bx\ \text{on the right side}\\\\a-ax-bx=-ax-c\qquad\text{add}\ ax\ \text{to both sides}\\\\a-bx=-c\qquad\text{subtract}\ a\ \text{from both sides}\\\\-bx=-a-c\qquad\text{divide both sides by}\ -b\neq0\\\\x=\dfrac{-a-c}{-b}\\\\x=\dfrac{a+c}{b}$

$2)\\2(3x-5a)+9(2a-7b)+3(5a-2x)=0\\\\\text{use the distributive property}\ a(b+c)=ab+ac\\\\(2)(3x)+(2)(-5a)+(9)(2a)+(9)(-7b)+(3)(5a)+(3)(-2x)=0\\\\6x-10a+18a-63b+15a-6x=0\qquad\text{combine like terms}\\\\(6x-6x)+(-10a+18a+15a)-63b=0\\\\23a-63b=0\qquad\text{add}\ 63b\ \text{to both sides}\\\\23a=63b\qquad\text{divide both sides by 23}\\\\a=\dfrac{63b}{23}\\\\if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number\\\\if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)$

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4 years ago

From a window 20 feet above the ground, the angle of elevation to the top of a building across

Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

$\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},$

and from the right-angled triangle WAB, we have'

$\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.$

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0

3 years ago

Can someone answer this for me pls!!!! 40 points!!

Bumek [7]

Answer: x1 = 10

x2 = 16

x3 = 28

Step-by-step explanation:

8 0

3 years ago

Can someone help me with this? (The ratio of 7th grade students to 8th grade students in a soccer league is 17:23. If there are

IrinaVladis [17]

Answer:

Step-by-step explanation:

You add 17 and 23 and you get 40 so 40=200 and divide 40 and 200 by 5 and so 1/40 =5 so 5x17=85.

sorry if I got it wrong I'm trying.

6 0

4 years ago