Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have
and so you would need to add 15 L of pure water to get the desired concentration of acid.
Answer:
See below ↓↓
Step-by-step explanation:
<u>Finding the radius</u>
- C = 2πr
- 25 = 2 x 3.14 x r
- r = 25 / 6.28
- r = 3.98 cm ≅ 4 cm
<u />
<u>Surface Area</u>
- 4πr²
- 4 x 3.14 x 4 x 4
- 3.14 x 64
- 200.96
- <u>201 cm²</u>
<u></u>
<u>Volume</u>
- 4/3πr³ = 4πr² x r/3
- 201 x 4/3
- 67 x 4
- <u>268 cm³</u>
Answer:
9535 g
9225 g or
9714 g
Step-by-step explanation:
4523g+5012g =9535g
4523g+4702g= 9225g
5012+4702g=9714g
I don't know all of them but I can tell you that B and E are answers that you should check.
Answer:
<BOC = 100*
Step-by-step explanation:
