Question

1.What number, when substituted for x in the following problem, will make the problem true? 6x + 8x = 10x

Answer 1

6x + 8x = 10x --> 14x=10x --> x always = 0

Answer 2

Answer:

1.) If you substitute the number 2 for x in the problem, you’ll make it true.

6x + 8x = 10x

62 + 82 = 102

36 + 64 = 100

100 = 100

2.) Insert two radical signs into the problem like this to make it true:

5 = 5 √4 + √4 + 4⁄4

5 = 2 + 2 + 1

5 = 5

3.) a. 42 = 4 × 4 = 16

b. 62 = 6 × 6 = 36

c. 132 = 13 × 13 = 169

d. 102 = 10 × 10 = 100

4.) a. 13 = 1 × 1 × 1 = 1

b. 23 = 2 × 2 × 2 = 8

c. 43 = 4 × 4 × 4 = 64

d. 83 = 8 × 8 × 8 = 512

5.) a. 2 × 2

b. 8 × 8 × 8 × 8

c. 12 × 12 × 12

d. 20 × 20 × 20 × 20 × 20

6.) a. 52

b. 74

c. 23

d. 95

7.) a. 33 = 3 × 3 × 3 = 27

b. 142 = 14 × 14 = 196

c. 125 = 12 × 12 × 12 × 12 × 12 = 248,832

d. 90 = 1 (Any number to the zero power equals 1.)

e. 44 = 4 × 4 × 4 × 4 = 256

f. 171 = 17 (Any number to the first power equals itself.)

8.) a. 7.6 × 103

(103 = 1,000 and 7.6 × 1,000 = 7,600)

b. 2.34 × 104

(104 = 10,000 and 2.34 × 10,000 = 23,400)

c. 1.67 × 105

(105 = 100,000 and 1.67 × 100,000 = 167,000)

d. 2 × 109

(109 = 1,000,000,000 and 2 × 1,000,000,000 = 2,000,000,000)

9.) a. 97,000

(9.7 × 10 × 10 × 10 × 10 = 97,000)

b. 700,000

(7 × 10 × 10 × 10 × 10 × 10 = 700,000)

c. 89,700,000

(8.97 × 10 × 10 × 10 × 10 × 10 × 10 × 10 = 89,700,000)

d. 32,000,000,000

(3.2 × 10 × 10 × 10 × 10 × 10 × 10 × 10 × 10 × 10 × 10 = 32,000,000,000)

10.) a. 4 (4 × 4 = 16)

b. 13 (13 × 13 = 169)

c. 8 (8 × 8 = 64)

d. 20 (20 × 20 = 400).

Step-by-step explanation:

answers are from Penn Foster