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Brut [27]
3 years ago
10

Is parallelogram EFGH a rectangle?

Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

No.

Step-by-step explanation:

I’m just eyeballing it, so no garantee, but it looks misshaspen, like some of the angles are not exactly 90 degrees.

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Can someone help (will give brainliest)
nikklg [1K]

Answer:

384

Step-by-step explanation:

8 x 6 = 48

48 x 2 = 96

12 x 10 = 120

6 x 12 = 72

8 x 12 = 96

96 + 120 + 72 +96 = 384

8 0
3 years ago
Read 2 more answers
Suppose it is known that 8 out of the 20 teams in the sample had a season winning percentage better than 0.500.
Ganezh [65]

Answer:

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

8 out of the 20 teams in the sample had a season winning percentage better than 0.500. This means that n = 20, \pi = \frac{8}{20} = 0.4.

95% confidence interval

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.1853

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.6147

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

3 0
4 years ago
Anna is making a fertilizer mix for her flower garden. She uses 2 cups of fertilizer to 12 quarts of water. How much fertilizer
goblinko [34]

Answer:

a

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Meng is constructing the perpendicular bisector of MN¯¯¯¯¯¯¯ . She placed the compass point on M, opened the compass to more tha
lana66690 [7]

Answer: She should keep the same compass opening, place the compass point back on point M, and draw an arc below the line segment MN.


Step-by-step explanation:

According to the rule of construction of perpendicular bisector, she should draw an arc both side of line segment without changing the opening of the compass.

So, her next step would be to take the third option, i.e. She should keep the same compass opening, place the compass point back on point M, and draw an arc below the line segment MN.


4 0
3 years ago
Read 2 more answers
A data set lists earthquake depths. The summary statistics arenequals=500500​,x overbarxequals=5.435.43​km,sequals=4.864.86km. U
Eva8 [605]

Answer:

C. H 0​:μ=5.00km   H1​:μ≠5.00km

z=\frac{5.43-5.00}{\frac{4.86}{\sqrt{500}}}=1.978    

p_v =2*P(z>1.978)=0.048

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is nto significantly different from 5.00.    

Step-by-step explanation:

Some previous concepts

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.

A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".

The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"

The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

Data given and notation    

\bar X=5.43 represent the average for the sample

s=4.86 represent the sample standard deviation for the sample    

n=500 sample size    

\mu_o =5.00 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to check if the population mean is equal to 5.00, the system of hypothesis would be:    

Null hypothesis:\mu = 5.00    

Alternative hypothesis:\mu \neq 5.00    

Since the sample size >30 and large, the estimator for the population deviation would be s, and we can use the z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{5.43-5.00}{\frac{4.86}{\sqrt{500}}}=1.978    

P-value    

Since is a two tailed test the p value would be:    

p_v =2*P(z>1.978)=0.048

In Excel we can us ethe following formula to find the p value "=2*(1-NORM.DIST(1.978;0;1;TRUE))"  

Conclusion    

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is nto significantly different from 5.00.    

8 0
3 years ago
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