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3 years ago

Help me with inequality

Mathematics

2 answers:

Hoochie [10]3 years ago

6 0

Answer:

C. x > 3

Step-by-step explanation:

As long as you don't multiply or divide by any negative numbers*, you can solve this the same way you would an equation.

3x +2 > x +8

3x > x +6 . . . . . . subtract 2

2x > 6 . . . . . . . . subtract x

x > 3 . . . . . . . . . .divide by 2; matches choice C

_____

* The complete rule is "as long as you don't use any order-changing operations, ...". There are some functions you can apply to both sides of the inequality that will change the ordering. Multiplication or division by a negative number is only one of many.

1 < 2

-1 > -2 . . . . . multiplication by -1 reverses the order

almond37 [142]3 years ago

3 0

Answer:

$x > 3$

Answer C is correct

Step-by-step explanation:

$3x + 2 > x + 8 \\ 3x - x > - 2 + 8 \\ 2x > 6 \\ \frac{2x}{2} > \frac{6}{2} \\ x > 3$

hope this helps

brainliest appreciated

good luck! have a nice day!

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Complete the parts in each step to find the area of each trapezoid?

Sergio039 [100]

The area of the trapezoid is 20 in².

Solution:

Given data:

Length of the bottom base = 7 in

Length of the top base = 3 in

Height of the trapezoid = 4 in

Step 1: Area of the trapezoid formula,

$$A=\frac{b_{1}+b_{2}}{2} \times h$

Step 2: Substitute the given values in the formula.

$$A=\frac{7+3}{2} \times 4$

Step 3: Add 7 and 3.

$$A=\frac{10}{2} \times 4$

Step 4: Divide 10 by 2, we get

$A=5 \times 4$

Step 5: Multiply 5 by 4, we get

A = 20 in²

The area given in the picture is wrong.

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8 0

2 years ago

Final questions I'm asking if you've been keeping up. Thanks in advance.

GaryK [48]

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5 0

3 years ago

We have n = 100 many random variables Xi ’s, where the Xi ’s are independent and identically distributed Bernoulli random variab

777dan777 [17]

Answer:

(a) The distribution of $X=\sum\limits^{n}_{i=1}{X_{i}}$ is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

Step-by-step explanation:

It is provided that random variables $X_{i}$ are independent and identically distributed Bernoulli random variables with p = 0.50.

The random sample selected is of size, n = 100.

(a)

Theorem:

Let $X_{1},\ X_{2},\ X_{3},...\ X_{n}$ be independent Bernoulli random variables, each with parameter p, then the sum of of thee random variables, $X=X_{1}+X_{2}+X_{3}...+X_{n}$ is a Binomial random variable with parameter n and p.

Thus, the distribution of $X=\sum\limits^{n}_{i=1}{X_{i}}$ is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

The sample size is large, i.e. n = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu=p=0.50$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05$

(c)

Compute the value of $P(\bar X>0.50)$ as follows:

$P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\$

$=P(Z>0)\\=1-P(Z$

*Use a z-table.

Thus, the value of $P(\bar X>0.50)$ is 0.50.

8 0

3 years ago

12x-39<9 and -4x+3<-6

gulaghasi [49]

Remember, you can do anything to an equation as long as you do it to both sides

and when multiply or divide by a negative in inequalities, flip the direction of the sign

12x-39<9
add 39 to both sides
12x<48
divde bothh sides by 12
x<4

-4x+3<-6
minus 3 both sides
-4x<-9
times both sides by -1 and flip sign
4x>9
divide both sides by 4
x>9/4

4 0

3 years ago

Read 2 more answers

Lowest common multiple of 9

ch4aika [34]

Is 3.

3×3=9

Hope this helps!

3 0

3 years ago