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Arturiano [62]
3 years ago
14

Emmanuel brought 28 lb of potting soil this week. This amount is 4 lb more than twice the amount of potting soil he brought last

week. Answer the following questions to find the number of pounds of soil emmanuel purchased last week.
(a) what is the unknown information

(b) let p represent the unknown information. Write an equation to model the problem.

(c) which number, 10,11, or 12 will solve the equation in part (b)? show your work

(d) how many pounds of potting soil did emmanuel buy last week?
Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0
(a) how much potting soil he bought last week
(b) 28 = 2p + 4
(c) 28 = 2p + 4....subtract 4 from both sides
     28 - 4 = 2p...simplify
     24 = 2p...divide both sides by 2
     24/2 = p....simplify
     12 = p......12 solves the equation
(d) He bought 12 lbs of potting soil last week
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ira [324]

Answer:

x=65

Each NBA team can have a maximum of 15 players, 13 of which can be active each game.

65/5=13 so it's safe to say tgat 5 team can be crated

Step-by-step explanation:

x/5-2=11-->transposing x/5=11+2---->x=13×5--->x=65

verification 65/5-2=11--->13-2=11

4 0
2 years ago
23.21
alisha [4.7K]

The equation that represents the relationship between the number of liters, x, and the number of liquid pints, y is y = 2.11x

<h3>How to determine the equation?</h3>

The attached table of values represents the missing piece in the question.

Start by calculating the rate of change using:

m = (y2 - y1)/(x2 - x1)

This gives

m = (14.77 - 10.55)/(7- 5)

Evaluate

m = 2.11

The equation is then calculated using:

y = m(x - x1) + y1

This gives

y = 2.11(x - 5) + 10.55

Evaluate

y = 2.11x - 10.55 + 10.55

y = 2.11x

Hence, the equation that represents the relationship between the number of liters, x, and the number of liquid pints, y is y = 2.11x

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

4 0
2 years ago
Find the value of x below
ehidna [41]

Answer:

x=58 degrees

Step-by-step explanation:

The angle DB is equal to 90 degrees, so if you subtract 32 from 90 you get x, which is 58.

3 0
3 years ago
Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of
tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A                          Sample B

x_A = 30                              x_B = 50

n_A = 100                             n_B =250

Solving (a): Standard error using formula

First, calculate the proportion of A

p_A = \frac{x_A}{n_A}

p_A = \frac{30}{100}

p_A = 0.30

The proportion of B

p_B = \frac{x_B}{n_B}

p_B = \frac{50}{250}

p_B = 0.20

The standard error is:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}

SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}

SE_{p_A-p_B} = \sqrt{0.00274}

SE_{p_A-p_B} = 0.052

Solving (a): Standard error using bootstrapping.

Following the below steps.

  • Open Statkey
  • Under Randomization Hypothesis Tests, select Test for Difference in Proportions
  • Click on Edit data, enter the appropriate data
  • Click on ok to generate samples
  • Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A                          Sample B

x_A = 23                              x_B = 57

n_A = 100                             n_B =250

p_A = 0.230                          p_A = 0.228

So, we have:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}

SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}

SE_{p_A-p_B} = \sqrt{0.002475064}

SE_{p_A-p_B} = 0.050

5 0
3 years ago
Limit   
STatiana [176]

Rationalize the numerator:

\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}

This is continuous at x=0, so we can evaluate the limit directly by substitution:

\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14

5 0
3 years ago
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