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dmitriy555 [2]
3 years ago
8

Evaluate each limit Appreciate it!

Mathematics
1 answer:
Semenov [28]3 years ago
3 0

Answer:

\lim_{x\to 1^+} f(x)=5

Step-by-step explanation:

So we have the function:

f(x) = \left\{        \begin{array}{ll}            x+2 & \quad x \leq 1 \\            x^2+2x+2 & \quad x > 1        \end{array}    \right.

And we want to evaluate:

\lim_{x\to 1^+} f(x)

In other words, we want to evaluate the limit for f(x) as x approaches 1 <em>from the right. </em>

Since our x is approaching from the right, this means that we need to use the second equation. This is because the second equation is defined for all values <em>greater than</em> 1. So, if we approach from the right, we are using all values greater than 1. Therefore:

\lim_{x\to 1^+} f(x)

Replace f(x) with the second equation:

=\lim_{x\to 1^+} (x^2+2x+2)

Evaluate. Use direct substitution:

=(1)^2+2(1)+2

Square:

=1+2(1)+2

Multiply:

=1+2+2

Add:

=5

Therefore:

\lim_{x\to 1^+} f(x)=5

And we're done!

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