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Darina [25.2K]
2 years ago
12

I need help with this please!!!

Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
7 0

Answer:

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(08.01)Consider the following system of equations:
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Lines y = −2x + 3 and y = 3x – 5 intersect the x-axis.

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There are 5 candy canes for every 9 presents. How many candy canes are there when there are 108 presents
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When there are 108 presents, there are 60 candy canes

Step-by-step explanation:

candy canes : presents = 5:9

5/9 = x/108

cross multiply:

(5) (108) = 9x

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x = 60

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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

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=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




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Y = 3x + 2<br><br> y = 6x + 3<br><br> y = 4x − 1
grandymaker [24]
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