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beks73 [17]
3 years ago
9

How do you solve 9^x=3^40?

Mathematics
2 answers:
patriot [66]3 years ago
8 0

Answer:  x = 20

<u>Step-by-step explanation:</u>

Manipulate the bases so they are the same, then set the exponents equal to each other and solve for x:

9ˣ = 3⁴⁰

(3²)ˣ = 3⁴⁰

3²ˣ = 3⁴⁰

2x = 40

 x = 20

alex41 [277]3 years ago
4 0

Answer:

We have 9 = 3^2;

Then, 9^x = (3^2)^x = 3^(2x);

We solve  3^(2x) = 3^40;

2x = 40;

x = 20 ÷ 2;

x = 10;

Step-by-step explanation:


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