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lesya692 [45]
4 years ago
6

How to solve mean median and mode

Mathematics
1 answer:
cestrela7 [59]4 years ago
8 0
You can solve the median by putting all the numbers in order. Then cross off one at a time at the start, then cross off the one at the end, then keep going until you get to one.

You can solve the mode by looking for the most frequent number. I remembered that by looking at mode and seeing MO and remembering most often.

I hope this helps :-)
You might be interested in
2.3 divided by what equals 0.23
choli [55]

Answer: 0.529


Step-by-step explanation: 0.529/2.3=0.23


5 0
3 years ago
A 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia). At a summer cam
bagirrra123 [75]

Answer:

Probability that at least one of them suffers from arachnophobia is 0.5160.

Step-by-step explanation:

We are given that a 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia).

Also, At a summer camp there are 10 teenagers sleeping in each tent.

Firstly, the binomial probability is given by;

P(X=r) =\binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,....

where, n = number of trials(teenagers) taken = 10

           r = number of successes = at least one

          p = probability of success and success in our question is % of

                the teenagers suffering from arachnophobia, i.e. 7%.

Let X = Number of teenagers suffering from arachnophobia

So, X ~ Binom(n= 10,p=0.07)

So, probability that at least one of them suffers from arachnophobia

= P(X >= 1) = 1 - probability that none of them suffers from arachnophobia

= 1 - P(X = 0) = 1 - \binom{10}{0}0.07^{0}(1-0.07)^{10-0}

                       = 1 - (1 * 1 * 0.93^{10} ) = 1 - 0.484 = 0.5160 .

Therefore, Probability that at least one of them suffers from arachnophobia is 0.5160 .

3 0
3 years ago
A backstroke swimmer on the Brown Middle School swim team is required to spend at least 70% of his or her total laps practicing
Serjik [45]
There is no table so I cannot help you other than to say
to find the answer multiply the time swimming of each participating swimmer by .7 and you shall get your time.
3 0
4 years ago
Which of the following comparisons is true? 24,762 = 24,662 335,989 > 335,998 454,909 887,012
ratelena [41]
454,909 < 887,012 <===
8 0
3 years ago
Please help me I really need help i beg of u due today
nasty-shy [4]

Answer:

The volume of the observatory is 497.43 feet^{3}

Step-by-step explanation:

i) The diameter of the floor is 10 feet. The floor is circular and has a radius,          

    r =  \frac{10}{2} = 5 feet.

   Therefore the area of the circular floor of the observatory

     = \pi r^{2}      =   3.14159 × 5^{2}    =    78.54 feet^{2}

ii) The observatory is made up of two parts

  a)  3 foot tall cylinder

      ∴ volume of cylinder = \pi r^{2}   × h

                                         = 78.54 × 3

                                         = 235.62 feet^{3}

   b)  hemisphere = \frac{1}{2} × \frac{4}{3} \pi r^{3} = 0.6667 × 78.54 × 5   =  261.81 feet^{3}

    c) Therefore the total volume of the observatory is = a) + b)

         = 235.62 + 261.81 =   497.43 feet^{3}

5 0
3 years ago
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