How to solve mean median and mode

Please help me!! I am struggling... I will not accept nonsense answers!

telo118 [61]

Answer:

y = 110°

Step-by-step explanation:

The inscribed angle CHF is half the measure of its intercepted arc CDF

The 3 arcs in the circle = 360°, thus

arc CDF = 360° - 160° - 60° = 140°, so

∠ CHF = 0.5 × 140° = 70°

∠ CHF and ∠ y are adjacent angles and supplementary, thus

y = 180° - 70° = 110°

6 0

2 years ago

Write the exact value solution and an approximation for 10^4x=25

Murrr4er [49]

Answer:

exact value: $x= \frac{log25}{4}$

approximate: x=0.349485

Step-by-step explanation:

Exact Value:

$10^{4x} = 25$

$log (10^{4x})= log 25$

$4x = log 25$

$x= \frac{log25}{4}$

Approximate:

$x= \frac{log25}{4}$

$x=1.39794/4\\$

$x=0.349485$

6 0

2 years ago

Brooks built two similar wooden chests in the shape of rectangular prisms. She used 16 pints of paint to cover the outside of th

tester [92]

Choices: A. 16/9 B. 4/3 C. 32/9 D. 64/27

Given:
number of pints used for larger chest = 16 pints
number of pints used for smaller chest = 9 pints

Ratio of the volume of the larger chest compared to the smaller chest.

We will use the number of pints used in lieu of the volume of each chest.

16 / 9 is the ratio. Choice A.

3 0

3 years ago

Its for science but its got math involved its got to do with speed distance and time

KIM [24]

distance:1, 1, 1.3, 1.5, 2, 2.3, 2.5, 3 ,3.2, 4

time. :1, 2, 3 , 4 , 5 , 6 , 7 , 8 ,. 9 ,10

distance:1.5, 2, 3.2, 4.2, 5, 6, 7, 8

time. : 1 , 2, 3 , 4. , 5, 6, 7, 8

<h3>at 5 seconds which travelled the greatest distance : snail 2</h3>

<h3>which travelled a greater distance:snail 2</h3>

<h3>what is the speed of snail 1 at 8 second :</h3>

distance = 3. Time = 8

speed = distance

time

speed = 8

3

speed =2.66

approximately = 2.7. or 3

7 0

3 years ago

HELP PLEASE! I don't understand and have been stuck on this problem for a whole hour. Please explain. Also, none of the answers

Lyrx [107]

The altitude is the mean proportional between the left and right parts of the hyptenuse

$\cfrac{FI}{GI} = \cfrac{GI}{HI} \ \ \Rightarrow \ \ \cfrac{FI}{15} = \cfrac{15}{16} \ \ \Rightarrow \ \ FI= \cfrac{15 \cdot 15 }{16} \approx 14.1$

Answer: 14.1

5 0

2 years ago

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