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slega [8]
3 years ago
5

Plz help due tomorrow

Mathematics
2 answers:
Zanzabum3 years ago
7 0

Answer:

D, or the last option

Step-by-step explanation:

chubhunter [2.5K]3 years ago
3 0

Answer:

1/2-5d

Step-by-step explanation: Commutative property you have to switch the order of the terms. Since your problem was -5d+1/2 just flip it, 1/2-5d.

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You ask 200 randomly chosen students to name their favorite ice cream flavor. There are 1800 students in the school. Based on th
Kaylis [27]

Answer:

351

Step-by-step explanation:

Complete question :

Vanilla= 36

Chocolate=21

Strawberry=24

Chocolate Chip=39

SOLUTION:

39 chocolate chip to 200 students = x chocolate chip to 1800 students

39/200 = x / 1800

Solving for 'x'

(200)(x) = (39)(1800)

200x = 70200

x = 70200/200

x = 351

OR

39 out of 200 picked chocolate chip

therefore, 39/200 = 0.195 = 19.5%  ( 32.5% chose chocolate chip)

19.5% of 1800 = 0.195(1800) = 351 students

6 0
3 years ago
Which of the following is most likely the next step in the series?
REY [17]

Answer:

D

Step-by-step explanation:

blue and next line

7 0
3 years ago
If one rooster can wake up 10 hens, then how many hens can 3 roosters wake up?
Tresset [83]
I’m pretty sure the answer is 30... right? Because you’d multiply 10 and 3
3 0
4 years ago
For less than a number is no more than six
photoshop1234 [79]

Answer:

1

Step-by-step explanation:

lowest

3 0
3 years ago
g A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a
Helga [31]

Answer:

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.02})^{2}

n = 2401

The sample size needed is 2401.

7 0
3 years ago
Read 2 more answers
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