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KATRIN_1 [288]
3 years ago
6

7j+5-8k when j=0.5 and k=0.25

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

<em>6.5</em>

Step-by-step explanation:

To perform this kind of exercise, it is necessary to replace the value indicated in each variable each time you find the variable in the equation.

7j+5-8k

If j=0.5 and k=0.25, replace the value of each variable.

7(0.5)+5-8(0.25)=

now perform the indicated operations

7(0.5)+5-8(0.25)=3.5+5-2=6.5

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Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

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Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

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Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

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