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maxonik [38]
3 years ago
12

Sonji has $5.25 in nickels and dimes.The coin value can be modeled by the equation 0.10 d plus 0.05 n equals 5.25, where d repre

sents the number of dimes and n represents the number of nickels. If Sonji has 21 dimes, how many nickels does she have?
35
42
63
105
Mathematics
2 answers:
Sedaia [141]3 years ago
8 0

Answer:

Im not sure but i think it is 42

Step-by-step explanation:

djverab [1.8K]3 years ago
6 0

Answer:

<h2>Sonji has 63 nickels.</h2>

Step-by-step explanation:

Here we just have to take the given expression, and replace the amount of dime Sonji has.

So, we know that the situation is modeled by:

0.10d+.0.05n=5.25

Where d and n are dimes and nickels respectively. The model make totally sense, because each dime values 10 cents or $0.10, and each nickel values 5 cents or $0.05.

So, if Sonji has 21 dimes, we replace this in the model and solve for n:

0.10d+.0.05n=5.25\\0.10(21)+0.05n=5.25\\2.1+0.05n=5.25\\0.05n=5.25-2.1\\n=\frac{3.15}{0.05}\\ n=63 \ nickels

Therefore, according with this result, Sonji has 63 nickels.

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3 years ago
A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys
Luba_88 [7]

Answer:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would earn a certificate of recognition from the fitness association

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the time for this event of a population, and for this case we know the distribution for X is given by:

X \sim N(470,60)  

Where \mu=470 and \sigma=60

NOTE: For this case the fastest 10% is on the lower tail of the distribution

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.9   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would  earn a certificate of recognition from the fitness association

4 0
3 years ago
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