Answer:
/*
Find Largest and Smallest Number in an Array Example
This Java Example shows how to find largest and smallest number in an
array.
*/
public class FindLargestSmallestNumber {
public static void main(String[] args) {
//array of 10 numbers
int numbers[] = new int[]{32,43,53,54,32,65,63,98,43,23};
//assign first element of an array to largest and smallest
int smallest = numbers[0];
int largetst = numbers[0];
for(int i=1; i< numbers.length; i++)
{
if(numbers[i] > largetst)
largetst = numbers[i];
else if (numbers[i] < smallest)
smallest = numbers[i];
}
System.out.println("Largest Number is : " + largetst);
System.out.println("Smallest Number is : " + smallest);
}
}
/*
Output of this program would be
Largest Number is : 98
Smallest Number is : 23
*/
Explanation:
Answer:
Sure. In Unit test 5, it's looking for 1 instead of 0. You are returning 0 instead of 1.
0 requires 1 digit to express it and should therefore return 1.
In line 6, change the 0 to a 1.
Conduct a query and set the criteria as = August 8, 2008. I'm not sure if this is the right answer, but that's what I think it is.
Chronological Order. ...
Logical Order. ...
Climactic Order. ...
Random Order. ...
Spatial Order.
B is my answer im guessing
