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Sholpan [36]
3 years ago
15

A large IPv4 datagram is fragmented into 4 fragments at router 1 to pass over a network with an MTU of 1500 bytes. Assume each f

ragment is larger than 900 bytes. Then, each fragment arrives at router 2, which wants to forward the fragments over a network with an MTU of 900 bytes to deliver to the destination.
How many fragments will arrive at the destination host?
Computers and Technology
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

8

Explanation:

Having in mind that all the given 4 fragments are larger than 900 bytes and smaller than 1500 bytes, this will make router 2 to fragment each fragment by router 1 into 2 fragments .

Hence, 4*2 = 8 fragments will reach at destination host.

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Mila [183]

Answer:

option A

Explanation:

Option A.

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3 0
3 years ago
write a program in python to input 3 sides of a triangle. check if the triangle is equilateral, isosceles or scalene. use logica
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<h2>Type of Triangle - Python</h2>

In Geometry, a triangle is a three-sided polygon with three edges and three vertices. A triangle with vertices A, B, and C denoted ∆ABC.

<h3>Equilateral Triangle</h3>

A triangle is said to be an EQUILATERAL TRIANGLE if all the sides are equal in measure.

<h3>Isosceles Triangle</h3>

A triangle is said to be an ISOSCELES TRIANGLE if any two sides are equal in measure.

<h3>Scalene Triangle</h3>

A triangle is said to be a SCALENE TRIANGLE if none of the sides are equal in measure.

<h3>Here's our program:-</h3>

a = float(input("Enter the length of the first side of a triangle: "))

b = float(input("Enter the length of the

second side of a triangle: "))

c = float(input("Enter the length of the third side of a triangle: "))

if (a == b and b == c and c == a):

print("Equilateral Triangle.")

elif (a == b or b = c or c == a):

print("Isosceles Triangle.")

elif (a != b and b !=c and c != a):

print("Scalene Triangle.")

<h3>else:</h3>

print("Invalid Input.")

6 0
2 years ago
The power ratio 1.774 is equivalent to how many dB?
kvv77 [185]

Answer:

2.489 dB

Solution:

As per the question:

Power ratio, \frac{P'}{P} = 1.774

The Equivalent of this power ratio in decibel or dB is calculated by taking the log of the power ratio as below:

\frac{P'}{P}_{dB} = 10log_{10}\frac{P'}{P}

\frac{P'}{P}_{dB} = 10log_{10}\times 1.774 = 10\times 0.2489 = 2.489 dB

Thus the value of the power ration in decibel comes out to be 2.489 dB

3 0
3 years ago
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