A large IPv4 datagram is fragmented into 4 fragments at router 1 to pass over a network with an MTU of 1500 bytes. Assume each f
1 answer:
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Answer:
The algorithm:
Input days
sum = 0
for i = 1 to
input text
sum = sum + text
end for
average = sum/days
print average
The program in pascal:
var days, sum, text, i:integer;
var average : real;
Begin
write ('Days: '); readln(days);
sum:=0;
for i := 1 to do
write ('Text: '); readln(text);
sum:=sum+text;
end;
average := (sum/days);
writeln ('The average text is' , average);
End.
Explanation:
This declares all variables
var days, sum, text, i:integer;
var average : real;
This begins the program
Begin
This gets the number of days from the user
write ('Days: '); readln(days);
Initialize sum to 0
sum:=0;
This iterates through the days
for i := 1 to do begin
This gets the text for each day
write ('Text: '); readln(text);
This sums up the texts
sum:=sum+text;
End loop
end;
Calculate average
average := (sum/days);
Print average
writeln ('The average text is' , average);
End program
End.
Answer:
Check the explanation
Explanation:
#include <iostream>
using namespace std;
void hex2dec(string hex_num){
int n = 0;
//Loop through all characters in string
for(int i=0;i<hex_num.size();i++){
//take ith character
char c = hex_num[i];
//Check if c is digit
if(c>='0' && c<='9'){
n = 16*n + (c-48);
}
//Convert c to decimal
else{
n = 16*n + (c-55);
}
}
cout<<hex_num<<" : "<<n<<endl;
}
int main()
{
hex2dec("EF10");
hex2dec("AA");
return 0;
}
The Output can be seen below :
