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oee [108]
4 years ago
9

“You can earn money by tutoring for $8 per hour and by walking dogs for $7.50 per hour. You have 15 h available to work. What is

the greatest number of hours you can spend walking dogs and still make at least $115?”
I need help
Mathematics
2 answers:
Klio2033 [76]4 years ago
7 0
<span>1.       </span><span>Given numbers:
=> $8 per hour by tutoring
=> $7.50 per hour by walking the dogs
=> You have 15 hours available
=> You need to make atleast $115 in walking the dogs.

let’s assign a variable to use.
Let a = tutoring
Let b = walking the dogs
=> a + b = 15
=> 8a + 7.5b = 115
=> 8a + 7.5(15 - a) = 115
=> 8a = 112.5 = 115
=> 8a = 115 – 112.5
=> 8a = 2.5
=> 8a / 8 = 2.5 / 8
=> a = 0.3125
=> b = 15 – 0.3125
=> b = 14.6875</span>



Ivenika [448]4 years ago
3 0

Answer:

14.6875

Step-by-step explanation:

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\huge\boxed{Answer\hookleftarrow}

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# ꧁❣ RainbowSalt2²2² ࿐

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madreJ [45]

Answer:

x = 3 + 4\sqrt{3}

Step-by-step explanation:

OPQ is a right angle triangle.

<u>Using Pythagoras</u>

x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0

<u>Using quadratic formula</u>

<u />x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}

x = 3 + 4\sqrt{3} = 9.928(4s.f.)

             OR

x = 3 - 4\sqrt{3} = -3.928(4s.f.) (Length can't be negative)

∴ x = 3 + 4\sqrt{3}

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