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natka813 [3]
3 years ago
6

Find the sum. Write your answer in simplest form. 2 1/2+ 5 5/8

Mathematics
2 answers:
emmasim [6.3K]3 years ago
6 0

Answer:

8 1/8

Step-by-step explanation:

2 4/8 plus 5 5/8

4/8 because it equals to 1/2

Lera25 [3.4K]3 years ago
6 0

Answer:

8 1/8

Step-by-step explanation:

2 1/2+ 5 5/8

2 4/8 + 5 5/8

7 9/8

8 1/8

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Are the equations m + 3 = -5 and m = -2 equivalent?​
guajiro [1.7K]
M + 3 = 5
-3 -3

m = -2
m= -2

yes the equations are equivalent
5 0
3 years ago
what percent of 150 is 96? .64% 6.4% 156% 64% find 225% of 3.6. 810 8.1 81 .81 135% of t is 63. t = 46.67 t = 85.05 t = 850.5 t
Andre45 [30]
1.To find the percentage of 150 is 96 you do:96 divided by 150 multiply by 100=64%
2. Multiply 3.6 by 225%
=8.1
3. 46.6 repeated
7 0
4 years ago
Read 2 more answers
It costs $0.60 per ft² to cover a right triangular field with sod. The side lengths of the field are 300 ft, 400 ft, and 500 ft.
algol [13]
In this triangle, we know base & perpendicular are 300 & 400 'cause 500 is the longest side which is hypotenuse 

Now, Area of a triangle = ab/2 = (300)(400)/2 = 120000/2 = 60000

As cost for 1 ft² = $0.60
cost for 60000 ft² = 60000 * 0.60 = $36000

In short, Your Answer would be Option A

Hope this helps!
8 0
4 years ago
Read 2 more answers
Someone please help me will give BRAILIEST!!!!!
alina1380 [7]
The answer would be a . $43.2 because your multiplying the number by 0.08
8 0
3 years ago
Read 2 more answers
Find the remainder when x^5 - 3x^3 + x - 5 is divided by x - 2​
Viktor [21]

<u>Given</u><u> info</u><u>:</u><u>-</u> Find the remainder when x^5 - 3x^3 + x - 5 is divided by x - 2

<u>Solution:</u><u>-</u>

Given,

p(x) = x^5 - 3x^3 + x - 5 , g(x) = x - 2

Let g(x) = x-2 will be the factor of p(x) if p(2) = 0.

Now, p(x) = x^5 - 3x^3 + x - 5

p(2) = (2)^5 - 3(2)^3 + 2 - 5

= (2*2*2*2*2) - 3(2*2*2) + 3 - 5

= 32 - 3(8) + 3 - 5

= 32 - 24 + 3 - 5

= 31 - 24 - 2

= 31 - 26

= 5 Remainder.

Hence, when x^5 - 3x^3 + x - 5 is divided by x - 2 , we get the remainder as 5.

4 0
3 years ago
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