All categories

3 years ago

Need help??????!!!!! Thank you

SAT

2 answers:

gavmur [86]3 years ago

8 0

Answer:

TELLEEEEEE ME

Explanation:

whad o t

Snowcat [4.5K]3 years ago

3 0

Umm did you forget the picture because I can’t tell what you need help with

You might be interested in

Under Nazi rule, the university curriculum was changed to place the most emphasis on history. engineering. mathematics. philosop

ch4aika [34]

Answer:

history

Explanation:

6 0

3 years ago

Δpqr is located at p (−3, −3), q (0, 0), and r (3, −3). Which statement correctly classifies δpqr? δpqr is a scalene triangle. Δ

Anit [1.1K]

Answer:

The Third choice- Δpqr is an equilateral triangle

Explanation:

If you put it on the graph and make the triangle on the graph. You get your answer.

7 0

3 years ago

Which answer choice is a solution to the inequality mc001-1. Jpg? –1 1 1. 5 0.

andriy [413]

Answer:

the solution to the inequality is 10511

Explanation:

8 0

3 years ago

If 5x=3 and 3y=5 , what is the value of x/y?

WITCHER [35]

Explanation:

5x=3

x=3

5

3y=5

y=5

3

now,

=x/y

=3/5÷5/3

= 9

5

hope it helps.

8 0

3 years ago

Read 2 more answers

Students in a statistics class are conducting a survey to estimate the mean number of units students at their college are enroll

Andrew [12]

Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 49 - 1 = 48 df, is t = 2.0106.

Hence:

$\overline{x} - t\frac{s}{\sqrt{n}} = 12.2 - 2.0106\frac{1.6}{\sqrt{49}} = 11.7$

$\overline{x} + t\frac{s}{\sqrt{n}} = 12.2 + 2.0106\frac{1.6}{\sqrt{49}} = 12.7$

The 95% confidence interval for the number of units students in their college are enrolled in is (11.7, 12.7).

More can be learned about the t-distribution at brainly.com/question/16162795

4 0

3 years ago