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aliina [53]
3 years ago
14

Can someone help me? Need everyone to go and report this account as many times as they can.... he cheated me out of 50 points an

d im mad. please help
charactersthehoodboi
SAT
2 answers:
aleksandr82 [10.1K]3 years ago
6 0

Answer:Yep! Hold on.

Explanation:

KengaRu [80]3 years ago
3 0
You can do that ? I had no clue tell me how so I can do so
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Find δs o for the combustion of methane to carbon dioxide and liquid water.
mote1985 [20]

The entropy change ΔS for the combustion of methane to carbon dioxide and liquid water is -242.6 J/mol.K

<h3>What is the Entropy in a Chemical system?</h3>

In a chemical system, Entropy (ΔS) is a quantitative measure of the variety of possible ways to disperse energy inside a chemical system.

  • In an isothermal process, entropy is determined as the quantity of heat transmitted to a system.

The chemical reaction for the combustion of methane can be expressed as:

\mathbf{CH_{4(g)} + 2O_{2(g)} \to CO_{2(g)} + 2H_2O_{(l)}}

The standard entropy of the combustion is expressed as:

\mathbf{\Delta S^0 =(S^0 _{CO_{2}} + 2 \times S^0 _{H_{2}O} )+(-S^0 _{CH_{4}}  -2 \times S^0 _{O_{2}} })

Replacing the standard entropies of the compounds into the above equation, we have:

\mathbf{\Delta S^0 =(213.8 \8 \ J/mol.K + 2 \times69.92 \ J/mol.K  )+(-186.16 \ J/mol.K -2 \times 205.04 \ J/mol.K})

\mathbf{\Delta S^0 =-242.6 \ J/mol.K}

Learn more about entropy here:

brainly.com/question/6364271

6 0
2 years ago
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/s2 . The acce
Thepotemich [5.8K]
That's some crazy equations...is there more to the question?
3 0
3 years ago
To prevent collisions and violations at intersections use the
andrew11 [14]

Answer: Delayed acceleration technique

Explanation:

4 0
2 years ago
Ms. Sanchez’s students were asked how many hours they spend participating in organized sports each week. Each row of the table r
slava [35]

The mean of a dataset is the average of the dataset.

The mean of the sample in the third row is 2.2

The dataset is given as:

5 5 3 0 6 2 2 4 5 2 3 4 3 0 1 4 0 4 3 6

From the complete question, the samples in the third row are:

Sample: 3 4 3 0 1

The mean of a dataset is calculated using:

\bar x = \frac{\sum x}{n}

Where:

n = 5 i.e. the number of samples

So, we have:

\bar x = \frac{3 + 4 + 3 + 0 + 1}{5}

Add the expressions in the numerator

\bar x = \frac{11}{5}

Divide 11 by 5

\bar x = 2.2

Hence, the mean of the sample in the third row is 2.2

Read more about mean at:

brainly.com/question/11887128

7 0
3 years ago
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Which word does not go with the other four?
GenaCL600 [577]

Answer:

stack isn't a fit out of these

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3 years ago
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