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vovangra [49]
3 years ago
14

At 5:00 pm sandra jean read a temperature of 42°f what was the temperature after it changed -6 degrees

Mathematics
1 answer:
viva [34]3 years ago
7 0
Just subtract the -6 from the 42.

42*
6-
----
36*
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Find the value of x, rounded to the nearest tenth
Lemur [1.5K]

Answer:

90+35+x=180

×=180-90+35

×=180-125

×=55

6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!
murzikaleks [220]

Answer:

Hi,

Step-by-step explanation:

x>=0

y>=0

x+y-5<=0 line passing through (0,5)  and (5,0) with (0,0) in minus region

2x-y-8<=0 line passing trough (0,-8) and (4,0) with (0,0) in minus region

Answer C

6 0
2 years ago
The distance y in miles traveled by a striped marlin in x hours is shown in the graph. Each ocean creature’s distance in miles i
julsineya [31]

9514 1404 393

Answer:

  swordfish

Step-by-step explanation:

The graph shows the marlin travels 50 miles in 1 hour, and 150 miles in 3 hours. These numbers can be compared directly to those given for the tuna (43.5 miles in 1 hour) and the wahoo fish (144 miles in 3 hours).

The speeds of the swordfish and shark are the coefficients of x in their respective equations. The swordfish travels 60 mph, so is faster than the marlin. The shark travels 31 mph, so is slower.

7 0
3 years ago
Pschological tests are often used to determine the hostility levels in people. High scores on the HLT pschological test correspo
algol13

Answer:  the correct answer is we are 95% confident that there is no statistically significant difference in the mean treatment  methods for hostility.  

Step-by-step explanation:

1)  Test for the equality of variances in the two groups to choose the appropriate t-test.  

H0: σ (1)^2 = σ (2)^2  

Ha: σ (1)^2 ≠ σ (2)^2  

Larger variance = 64  

Smaller variance = 49  

F = 1.30612  

Degrees of freedom 15 and 9  

Critical F from the table (with alpha=0.05) = 2.58  

Calculated F is smaller than critical F, so we use the pooled variance t-test.  

Sample 1 size 7  

Sample 2 size 8  

Sample 1 mean 79  

Sample 2 mean 84  

Sample 1 S.D. 7  

Sample 2 S.D. 8  

Pooled S.D = [(n1-1)s1^2+(n2-1)s2^2]/(n1+n2-2)

Pooled variance s = [(6)(49)+(7)(64))] / (13) =  (294+448)/13=742/13=57.076923

Pooled variance s^2 = 57.076923  

Standard error of difference in means = sqrt(1/n1+1/n2) times sqrt(s^2)  

Standard error of difference in means = (0.517549)(7.554927) = 3.910046 (denominator of t)  

Confidence interval = (mean1-mean2) +/- t SE  

t is the critical t with 24 degrees of freedom = 2.056  

(79 - 84) +/- (2.056) (3.910046)  

= (-13.04, 3.04)  

Interval encloses 0  

We are 95% confident that there is no statistically significant difference in the mean treatment  methods for hostility.  

4 0
3 years ago
A new car is purchased for 20700 dollars. The value of the car depreciates are 11% per year. What will the value of the car be,
ASHA 777 [7]

Answer: $5,744.61

Step-by-step explanation:

year 1 = -2,277

year 2 = -2026.53

year 3 = -1803.61

year 4 = -1605.21

year 5 = -1428.64

year 6 = -1271.49

year 7 = -1131.62

year 8 = -1007.17

year 9 = -896.36

year 10 = -797.76

year 11 = -710

you are subtracting 11% from each year.

5 0
3 years ago
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