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Anarel [89]
3 years ago
12

Need help to start this problem

Mathematics
1 answer:
shtirl [24]3 years ago
3 0

Answer:

have to make an x and y axis to get the answer

Step-by-step explanation:

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Are the ratios 13:14 and 1:2 equivalent?
eduard

Answer:

NO!

Step-by-step explanation:

They are not equivalent. We can check this. If you rewrite them as fractions 13/14 and 1/2, you can cross multiply and see if they are equal. Which they are not. Also, you could just guess.... think of 13:14 as 13 out of 14. And 1:2 as 1 out of 2. You can tell that 13/14 is much greater than 1/2.

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3 years ago
Find the area of the image below: Figure ABCDE is shown. A is at 6, 0. B is at negative 4, 5. C is at 2, 5. D is at 2, 9. E is a
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Where is the figure??
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Shawna won 51 pieces of gum playing basketball at her school's game night. Later, she gave three to each of her friends. She onl
Tanya [424]
15 friends got 3 pieces

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3 years ago
My question is the image
Nadya [2.5K]
1. Start at 2, then go up one over two for the next point.
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4 0
3 years ago
F(x)=x2-10 and g(x)=11-x find (f-g)(x)(f-g)(10) and (f/g)(x) if they exist
tester [92]

Answer:

(f - g)(x) = x^2 + x-21

(f - g)(10) = 89

(f/g)(x) = \frac{x^2 - 10}{11 - x}

Step-by-step explanation:

Given

f(x) = x^2 - 10

g(x) = 11  - x

Solving (1): (f-g)(x)

(f - g)(x) = f(x) - g(x)

Substitute values for f(x) and g(x)

(f - g)(x) = x^2 - 10 - (11 - x)

Open Bracket

(f - g)(x) = x^2 - 10 - 11 + x

(f - g)(x) = x^2 -21 + x

Reorder

(f - g)(x) = x^2 + x-21

Solving (2): (f-g)(10)

In (1)

(f - g)(x) = x^2 + x-21

So:

(f - g)(10) = 10^2 + 10-21

(f - g)(10) = 100 + 10-21

(f - g)(10) = 89

Solving (3): (f/g)(x)

(f/g)(x) = \frac{f(x)}{g(x)}

Substitute values for f(x) and g(x)

(f/g)(x) = \frac{x^2 - 10}{11 - x}

6 0
3 years ago
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